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2 years ago

1,100,000 divided by 2432.50

Mathematics

1 answer:

bija089 [108]2 years ago

4 0

1100000÷2432.5=452.21

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Is 1/4 greater than , less than , or equal to 0.4...

nata0808 [166]

¼ is equal to 0.25 because when you times by 4 you get a whole :)

4 0

3 years ago

Solve the equation for the indicated variable. 1. y= 3/8 (x+4) for x

madam [21]

Answer:

x=8y/3-4

Step-by-step explanation:

What we have to do to solve for X into re arrange the equation so that X is by itself on one side of the equation. To start we will divide both sides by 3/8 to move it away from the X side and we get

8y/3=x+4 then we will subtract both sides by 4 to get x all by itself

8y/3-4=x

I hope this helps and please don't hesitate to ask if there is anything still unclear!

6 0

3 years ago

Read 2 more answers

X^2-11x+30=2 Solve using quadratic formula or factoring

Pavel [41]

X^2-11x+28=0

(x-7)(x-4)=0

x-7=0
x=7

x-4=0
x=4

7 0

2 years ago

I WILL GAVE BRAINLIEST

Arte-miy333 [17]

Answer:

x < -14

Step-by-step explanation:

Step 1: Subtract 6 from both sides.

$-3x+6-6 > 48-6$
$-3x > 42$

Step 2: Divide both sides by -3 and flip the inequality sign.

$-3x/-3 > 42/-3$
$x < -14$

Therefore, the answer is x < -14.

4 0

1 year ago

Read 2 more answers

A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula

Ilia_Sergeevich [38]

Answer: A. $A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}$

B. A'(5) = 1.76 cm/s

Step-by-step explanation: Rate of change measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

$A=\pi.r^{2}$

So to find the rate of the area:

$\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}$

$\frac{dA}{dr} =2.\pi.r$

Using $r(t)=3-\frac{363}{(t+11)^{2}}$

$\frac{dr}{dt}=\frac{726}{(t+11)^{3}}$

Then

$\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]$

$\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}$

Multipying and simplifying:

$\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$

The rate at which the area is increasing is given by expression $A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$ .

B. At t = 5, rate is:

$A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}$

$A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}$

$A'(5)=\frac{2408693760\pi}{4294967296}$

$A'(5)=1.76268$

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

5 0

2 years ago