Answer:
Probability of (breath test / blood test) = 0.22/0.36.
Step-by-step explanation:
We are given that Police report that 78% of drivers are given a breath test, 36% a blood test, and 22% both tests.
Let Probability that drivers are given a breath test = P(X) = 0.78
Probability that drivers are given a blood test = P(Y) = 0.36
Probability that drivers are given both tests = = 0.22
<em>Now, we have to find Probability of (breath test/blood test);</em>
As we know that Conditional Probability of (A/B) is given by;
P(A/B) =
Similarly, P(breath test/blood test) = P(X/Y) =
= = 0.61
Therefore, required probability is 0.22/0.36 = 0.61.