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Sav [38]
3 years ago
6

Can someone answer this please? Okay so it says that something is made 3 times than the other item. The other item uses 13 beads

. So, what is 13 times 3?
Mathematics
2 answers:
kenny6666 [7]3 years ago
6 0
If you multiply them it would be 39. Hope this helps
V125BC [204]3 years ago
5 0

Answer:

13x3= 39

Step-by-step explanation:

10x3=30

3x3=9

30+9=39

Hope it helps!

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Can you please help me with this
Brrunno [24]
Just do 2000-586.40 and that will get you the remaining money they need to raise!:)
6 0
3 years ago
Read 2 more answers
Choose all the numbers that are common multiples of 3 and 12.
spayn [35]
<h3>Answers: 48 and 72</h3>

=========================================================

Explanation:

The number 12 is a multiple of 3 because 3*4 = 12.

So when looking for common multiples of 3 and 12, we simply need to look at multiples of 12.

The multiples of 12 are:

  • 12, 24, 36, 48, 60, 72, 84, 96, 120, ...

We see that 48 and 72 are on the list. The values 21, 27, 63, 81 are not on the list, so cross them out.

Now we could keep that list of multiples going to see if 844 is on there or not. A better method is to divide 844 over 12. If we get a whole number, then it's a multiple of 12.

844/12 = 70.333 approximately.

This shows that 844 is <u>not</u> a multiple of 12. So we cross 844 from the list.

Only 48 and 72 are multiples of 12 (and also multiples of 3).

6 0
2 years ago
WILL GIVE BRAINLIEST<br> FIND VOLUME<br> 60 is the area of the base
scoundrel [369]
Hey so yeah this can be a challenging problem, Vol (V) is much easier to solve than surface area (SA), but I'll show you how it's done, my friend.
First of all, V (prism) = area of base (B) × h
We know that the height (h) of this prism is given, which we'll need later on: h = 5 ft, and area of base (B) is given as 60 ft2
So V = 60 ft2 × 5 ft = 300 ft3

So now for the hard part... how to calculate the SA of this prism

IF YOU DON'T NEED SA FOR THIS TYPE OF PROBLEM, DO NOT PROCEED!!!
[VERY DETAILED]

means solving the dimensions (sides) of that pesky polygon base (B) or lid.
The most important things about polygons are:
1) is it regular (same angle ° and side length)??
2) How many sides or angles??

This has to be regular, because they give you no other info so it has to be, in order to solve. And then it has 5 sides and angles = regular pentagon. ("penta" means 5).

Now there are 360° in any circle, so:
take the central angles of where the sides meet at the center forming triangles (see drawing above), each of those (5) central <'s = 360/5 = 72°
Now the apex of each of these triangles = 72°
but with our 5 triangles, we need to find the height of each triangle -- which is the midpoint of the side (base (b) of triangle), and h is perpendicular to this b. By bisecting that apex angle of 72, it forms 2 equal right triangles of
72/2 = 36°. So each right triangle has 36, 90, and?? 180-36-90 = 90-36 = 54°
let's call the base (b) = 1 side of pentagon
= side (s)
Therefore (see 2nd image drawn above) tangent (tan) of € = opposite/adjacent, or
tan (54) = h÷1/2b --> h = [tan (54)]×(1/2)b
1/2b = h/[tan (54)] = h/1.38

Also the area of each of the larger 5 triangles A(t) = 1/2b×h, and that area A(t) × 5 = area of whole pentagon base A(B)
So now after all that... our A(B) given at beginning = 60ft2. let's put it all together:
1/2b = h/[tan (54)] = h/1.38
A(t) = 1/2b×h, and A(B) = 5×A(t)
which means that A(B) = 5×(1/2b×h)
AND since the other calculation shows that 1/2b = h/1.38, plug that value into the A(B) formula...
.
.
.

now that we have height (h) of each triangle, we can go back to our tan equation for the triangle: tan (54) = 1.38 = h/(1/2b)
--> 1/2×b = h/1.38 --> base (b) = 2h/1.38
b = 2(4.06 ft)/1.38 = 8.12 ft/1.38 = 5.90 ft, for which b us also the width of each rectangular side panel (w)
length (l) of these sides was given as height of the whole prism = 5 ft

NOW FINALLY... THE FINAL SURFACE AREA OF THE PRISM (SA) = (2×A(B)) + (5×rectangular side)
SA = (2×60 ft​2) + (5×(l×w)) = 120 ft2 + 5×5ft×5.9ft
SA = 120 ft2 + 147.62 ft2 = 267.62 ft2

4 0
3 years ago
A Gardner wants to add 39 pounds of nutrient a and 16 pounds of nutrient b to her garden. Each bag of brand x provides 3 pounds
ehidna [41]

Answer:

5 bags of brand x and 6 bags of brand y.

Step-by-step explanation:

Nutrient requirement for the garden:

39 pounds of nutrient a and

16 pounds of nutrient b

Component of each bag of brand x:

3 pounds of nutrient a and 2 pounds of nutrient b

Therefore, 5 bags of brand x will contain 15 pounds of nutrient a and 10 pounds of nutrient b

Component of each bag of brand y:

4 pounds of nutrient a and 1 pound of nutrient b

Therefore, 6 bags of brand y will contain 24 pounds of nutrient a and 6 pounds of nutrient b

Altogether, she should buy 5 bags of brand x and 6 bags of brand y to meet the nutrient requirement of the garden

3 0
3 years ago
Please help me! 10 pts and brainliest! please
luda_lava [24]

Answer:

B is correct

Step-by-step explanation:

i think

7 0
2 years ago
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