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FrozenT [24]
3 years ago
10

(13 - 10 1/3 )+ 2 2/3

Mathematics
2 answers:
sammy [17]3 years ago
7 0
Let's use PEMDAS
(13 - 10 1/3) + 2 2/3
10 1/3 can be rewritten to 31/3 
13 can be written to 31/1 then multiply both the 31 and 1 to get the same denominator to be able to subtract
39/3 -31/3 is 8/3
8/3 + 2 2/3
since it is already the same denominator
we can rewrite 2 2/3 to a improper fraction
8/3 + 8/3
16/3
is written to 5 1/3

Hope this helps :)
Komok [63]3 years ago
6 0
The answer is 17 hope it helps
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1 Distribute

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Prove or disprove: If a divides bc, then a divides b or a divides c
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David’s bank offers a 36-month Certificate of Deposit (CD) with an APR of 2.25%. Use the compound interest formula to answer the
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Using compound interest, it is found that:

a) A(8) = 2389.66

b) t = 31.15

c) P = 1870.85

Compound interest:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

  • A(t) is the amount of money after t years.  
  • P is the principal(the initial sum of money).  
  • r is the interest rate(as a decimal value).  
  • n is the number of times that interest is compounded per year.  
  • t is the time in years for which the money is invested or borrowed.

In this problem:

  • The APR is of 2.25%, hence r = 0.0225.
  • No information about the number of compounding per year, hence n = 1.

Item a:

P = 2000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

A(8) = 2000\left(1 + \frac{0.0225}{1}\right)^{8}

A(8) = 2389.66

Item b:

A(t) = 4000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

4000 = 2000\left(1 + \frac{0.0225}{1}\right)^{t}

(1.0225)^t = 2

\log{(1.0225)^t} = \log{2}

t\log{1.0225} = \log{2}

t = \frac{\log{2}}{\log{1.0225}}

t = 31.15

Item c:

A(3) = 2000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

2000 = P\left(1 + \frac{0.0225}{1}\right)^{3}

P = \frac{2000}{(1.0225)^3}

P = 1870.85

A similar problem is given at brainly.com/question/24850750

7 0
2 years ago
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