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Elena-2011 [213]

3 years ago

9

A circle has a circumference of 6. It has an arc of length 1.

1 answer:

s344n2d4d5 [400]3 years ago

6 0

Answer:

60 degrees

Step-by-step explanation:

s = r (theta)

(theta) = s/r

= 1 / (3/π) = π/3

as a degree π/3 x 180/π = 60

60 degrees

*Circumference = 2πr

6 = 2πr

r = 6/2π = 3/π

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Nikitich [7]

V=V of cube- V pyramid= 8^3- 7^2*8/3=512-49*8/3=512-130,67=381.33 cm^3

7 0

3 years ago

PLZZ HELP ILL GIVE BRAINLIEST AND DO NOT TYPE NO LINK WITH YALL LAZY AHH

Reil [10]

Answer:

D

Step-by-step explanation:

8 is LESS THAN 1/2x

so youd take those numbers and multiply by 1/2

C, B, and A are all under 8, so that would be wrong

when you multiply 1/2 with 17, you get 8.5 which is bigger than 8. then everything else above that is more than 8, therefore D is the right answer.

3 0

3 years ago

Read 2 more answers

Find the perimeter pf a rectangular parking lot that has a width of 3x+2 and a<br> length of 5x-7.*

uranmaximum [27]

Answer:

<u>Perimeter</u><u> </u><u>is</u><u> </u><u>1</u><u>6</u><u>x</u><u> </u><u>-</u><u> </u><u>1</u><u>0</u>

Step-by-step explanation:

${ \sf{perimeter = 2(length + width)}} \\ p = 2 \{(5x - 7) + (3x + 2) \} \\ p = 2(8x - 5) \\ p = 16x - 10$

8 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F

Wewaii [24]

Answer:

1. $P(x)$ ÷ $Q(x)$ ---> $\frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ ---> $\frac{2(6x - 1)}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ ---> $\frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x)$ --> $\frac{12}{(3x - 1)(-3x + 2)}$

Step-by-step explanation:

Given that:

1. $P(x) = \frac{2}{3x - 1}$

$Q(x) = \frac{6}{-3x + 2}$

Thus,

$P(x)$ ÷ $Q(x)$ = $\frac{2}{3x - 1}$ ÷ $\frac{6}{-3x + 2}$

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

$\frac{2}{3x - 1}*\frac{-3x + 2}{6}$

$\frac{2(-3x + 2)}{6(3x - 1)}$

$= \frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ = $\frac{2}{3x - 1} + \frac{6}{-3x + 2}$

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

$\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}$

$\frac{12x - 2}{(3x - 1)(-3x + 2)}$

$= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ = $\frac{2}{3x - 1} - \frac{6}{-3x + 2}$

$\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}$

$\frac{-24x + 10}{(3x - 1)(-3x + 2)}$

$= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}$

$P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}$

$P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}$

4 0

4 years ago

Use the box method to distribute and simplify (3x – 1)(-5x + 1)

Softa [21]

Answer:

-15x^2 +8x -1

Step-by-step explanation:

(3x – 1)(-5x + 1)=

3x(-5x) + 3x(1) - 1(-5x) -1 =

-15x^2 +3x +5x -1 =

-15x^2 +8x -1

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4 0

3 years ago