Ok, First you have to find the GCF of 120 and 90. When I got the answer I got a GCF of 30. I got 30 by multiplying all the number prime numbers 120 and 90 had, 2×3×5=30 What I did next was divide thirty by the number of cracker and also by the number of can of juice.
120÷30= 4
90÷30= 3
So as you can see there could be a maximum 30 of kid's. Each of the kids would receive 4 cans of juice and 3 packs of cheese crackers.
I hope you enjoyed my explanation. :)
What are the answers being provided ?
I'm sorry but do you ha e a picture of a flowchart
To find the GCF of the two terms, continuous division must be done.
What can be used to divide both terms such that there is not a remainder?
Start small, let's take 2. It could be a GCF.
Move up higher, say 3. Yes, it can be a GCF.
To see if there might be a greater common factor, divide the constants by 3.
48/3 = 16
81/3 = 27
Upon inspection and contemplation, there is no more common factor between 16 and 27. So, 3 is the GCF.
Moving on, when it comes to variables. The variable with the least exponents is easily the GCF. For the variable m, the GCF is m2 and for n, the GCF is n.
Combining the three, we have the overall GCF = 3m2n
