Answer:
Explanation:
Since we are not given the mole fraction of ethanol and water; we will solve this theoretically.
Using Raoult's Law:
For water:
where 
of water = 12.5 mmHg
Then, the vapor pressure of water:
For ethanol:
and the of ethanol = 32.1 mmHg
Then, the vapor pressure of ethanol:
The total vapor pressure 
The total vapor pressure = 
Answer:
Explanation:
By simple distillation, we can separate tow miscible liquids having sufficient difference in their boiling points.
By fractional distillation, we can separate the mixture of two or more miscible liquids for which the difference in their boiling point is less than 25k
Simple distillation is done using an air condenser or water condenser.
Fractionating column is fitted in between the distillation flask and the condenser for the process.
Simple distillation eg: mixture of water and acetone
fractional distillation eg: crude oil
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The balanced equation for the above reaction is as follows;
<span>Fe</span>₂<span>O</span>₃<span> + 3 CO --> 2 Fe + 3 CO</span>₂
<span>stoichiometry of CO to Fe is 3:2
molar volume states that 1 mol of any gas occupies a volume of 22.4 L
If 22.4 L contains 1 mol of CO
Then 3.65 L contains - 1/22.4 x 3.65 = 0.16 mol
3 mol of CO forms 2 mol of Fe
Then 0.16 mol of CO forms - 2/3 x 0.16 = 0.1067 mol of Fe
Therefore mass of Fe produced - 0.1067 mol x 55.8 g/mol = 5.95 g</span>
Answer:
P2=0.385atm
Explanation:
step one:
Given that the temperature T1= 60 Celcius
we can convert this to kelvin by adding 273k to 60 Celcius
we have T1= 333k
pressure P1= 0.470 atm
step two:
we know that the standard temperature is T2= 273K
Applying the temperature and pressure relationship we have
P1/T1=P2/T2
substituting our given data we have
0.47/333=P2/273
cross multiply we have
P2= (0.47*273)/333
P2= 128.31/333
P2=0.385 atm
