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Ket [755]
3 years ago
11

Question 2

Chemistry
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer: The volume of given ball is 21 L.

Explanation:

Given : Pressure = 1.0 atm,      no. of moles = 0.85 mol

Temperature = 25^{o}C = (25 + 273) K = 298 K

According to the ideal gas equation, formula used is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\1.0 atm \times V = 0.85 mol \times 0.0821 Latm/mol K \times 298 K\\V = 21 L

Thus, we can conclude that the volume is 21 L.

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Answer:

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Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

\frac{V_2}{T_2}=\frac{V_1}{T_1}

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

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3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

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Best regards!

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