Question

Question 2

Answer 1

Answer: The volume of given ball is 21 L.

Explanation:

Given : Pressure = 1.0 atm,      no. of moles = 0.85 mol

Temperature = $25^{o}C = (25 + 273) K = 298 K$

According to the ideal gas equation, formula used is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

$PV = nRT\\1.0 atm \times V = 0.85 mol \times 0.0821 Latm/mol K \times 298 K\\V = 21 L$

Thus, we can conclude that the volume is 21 L.