1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
const2013 [10]
2 years ago
13

The atmosphere of the planet Mars is 95.3% carbon dioxide, 2.6% nitrogen, 1.9% argon, with the remaining fraction being traces o

f free oxygen, carbon monoxide, sulfur dioxide, water and methane, among other gases. If the mean atmospheric pressure on Mars is 610 Pa, what is the partial pressure of nitrogen in the Martian atmosphere
Chemistry
1 answer:
kodGreya [7K]2 years ago
3 0

Answer:

Mean Partial pressure of Nitrogen in Mars' atmosphere = 15.86 Pa

Explanation:

According to Dalton's law of Partial Pressure, the total pressure exerted by a mixture of ideal gases (that do not react together) is the sum of the partial pressures of the individual gases that make up the mixture. It goes further to explain that the partial pressure of a gas in a mixture of gases is equal to its mole fraction of that gas multipled by the total pressure exerted by the mixture of gases.

Total Pressure exerted by the mixture of gases in the atmosphere on Mars = Mean atmospheric pressure on Mars = 610 Pa

Partial pressure of Nitrogen = (mole fraction or mole percentage of Nitrogen in the atmosphere) × (total pressure exerted by all the gases in the atmosphere)

Mole percentage of Nitrogen in the atmosphere of Mars = 2.6%

Partial pressure of Nitrogen = 2.6% × 610 = 15.86 Pa

Mean Partial pressure of Nitrogen in Mars' atmosphere = 15.86 Pa

Hope this Helps!!!

You might be interested in
What is the pH of a solution of 0.800 M KH2PO4, potassium dihydrogen phosphate?
Nookie1986 [14]
KH₂PO₄ hydrolyzes as;
H₂PO₄⁻ + H₂O ↔ H₃PO₄ + OH⁻
Let x amount of H₂PO₄⁻ has reacted with water then,
Kb₁ = [H₃PO₄][OH⁻] / [H₂PO₄⁻]
[H₂PO₄⁻] = 0.8-x M
Kb₁ = x² / (0.8 - x)
Given Ka₁ = 7.5 x 10⁻³
so Kb₁ = 1 x 10⁻¹⁴ / (7.5 x 10⁻³) = 1.33 x 10⁻¹²
From this information:
1.33 x 10⁻¹² = x² / 0.8
x = [OH⁻] = 1.03 x 10⁻⁶ M
pOH = - log (1.03 x 10⁻⁶) = 5.99
pH = 14 - pOH = 14 - 5.99 = 8.01 



3 0
3 years ago
A compound is composed of C, H and O. A 1.621 g sample of this compound was combusted, producing 1.902 g of water and 3.095 g of
vlada-n [284]

Answer: The molecular of the compound is, C_2H_3O

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=3.095g

Mass of H_2O=1.902g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.095g of carbon dioxide, \frac{12}{44}\times 3.095=0.844g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 1.902g of water, \frac{2}{18}\times 1.092=0.121g of hydrogen will be contained.

For calculating the mass of oxygen:

Mass of oxygen in the compound = (1.621)-[(0.844)+(0.121)]=0.656g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.844g}{12g/mole}=0.0703moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.121g}{1g/mole}=0.121moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.656g}{16g/mole}=0.041moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.041 moles.

For Carbon = \frac{0.0703}{0.041}=1.71\approx 2

For Hydrogen  = \frac{0.121}{0.041}=2.95\approx 3

For Oxygen  = \frac{0.041}{0.041}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 2 : 3 : 1

Hence, the empirical formula for the given compound is C_2H_3O_1=C_2H_3O

The empirical formula weight = 2(12) + 3(1) + 1(16) = 43 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{46.06}{43}=1

Molecular formula = (C_2H_3O_1)_n=(C_2H_3O_1)_1=C_2H_3O

Therefore, the molecular of the compound is, C_2H_3O

6 0
2 years ago
Will mark BRAINLIEST!! <br> PLEASE ANSWER I HAVE 5 MINS
maksim [4K]

Answer:

Explanation:

7A 0.2

7B cork

7C  Yes because the lighter it is the more likely it will float

7D  Density is one of the fundamental scientific principles of life. It can describe any everyday object. Despite its significance, students often struggle to understand what it really is. Density is a measurement of how much space or volume is packed in an object or substance.

8   property means a characteristic or trait that you can use to describe matter by observation, measurement, or combination.

3 0
2 years ago
What is the IUPAC name of KNO3<br>​
Tasya [4]
Answer: potassium nitrate


hope this helps
4 0
3 years ago
Read 2 more answers
What is the pOH of a solution with [OH'] = 9,0 x 10-7?
bearhunter [10]

Answer: D (6.04) is the best answer

Explanation:

pOH = - log [OH⁻]

pOH = - log (9.0 x 10⁻⁷)

pOH = 6.0457

6 0
3 years ago
Other questions:
  • A mineral sample is obtained from a region of the country that has high arsenic contamination. An elemental analysis yields the
    8·1 answer
  • The original amount of radioactive substance is 10 grams. After several years, 2.5 gtams of the substance is remaining. How many
    6·1 answer
  • What is the boiling point of water
    15·2 answers
  • How many atoms of fluorine are present in a molecule of carbon tetrafluoride CF4
    10·1 answer
  • In
    8·1 answer
  • The atomic mass is important because
    7·1 answer
  • What volume, in mL, of a 0.539 M solution of NaBH4 is required to produce 0.579 g of B2H6? H2SO4 is present in excess.
    6·1 answer
  • In the picture this is my last question pls.
    5·1 answer
  • De que material estan echos los marcapasos​
    11·2 answers
  • Why can you see a corona during a total solar eclipse?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!