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yaroslaw [1]
2 years ago
8

The difference between 7 7/8 - 3 1/4

Mathematics
2 answers:
Dima020 [189]2 years ago
8 0
You could convert them into improper fractions first. 7 7/8 should become 63/8 and 3 1/4 should become 13/4. Then, change both fractions so they share a common denominator. I'll use 8. 
63/8-26/8 = 37/8, which is then converted into 4 5/8.
Hope that helped you.
MaRussiya [10]2 years ago
6 0

The <em><u>correct answer</u></em> is:

4 5/8.

Explanation:

First we find the common denominator for the fractions. The first number that both 8 and 4 will go into is 8, so we will use 8.

We do not need to change the first number, as it is already in eighths.

For the second fraction: We can change 4 to 8 by multiplying by 2. Whatever we do to the denominator, we must do to the numerator, so we have 1*2 = 2. This gives us

7 7/8 - 3 2/8 = 4 5/8

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Find (f −1)'(a).<br><br> f(x) = 4 + x2 + tan(πx/2), −1 &lt; x &lt; 1, a = 4
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Answer:

The  solution  is   (f^{-1})'(a) = \frac{2}{\pi }

Step-by-step explanation:

From the question we are told that

      The  function is  f(x) =  4 +  x^2  + tan [\frac{ \pi x}{2} ] ,     -1 <  x  <  1  a =  4

Here we are told find  (f^{-1}) (a)

Let equate

     f(x) =  a

So  

      4 +  x^2  + tan[\frac{\pi x }{2} ] =  4

       x^2  + tan[\frac{\pi x }{2} ]  =  0

For the equation above to be valid x must be equal to 0

  Now when x = 0

       f(0) = 4+0^2 + tan [\frac{ \pi * 0}{2} ]

=>      f(0) =  4

=>  0 =  f^{-1} (4)

Differentiating  f(x)

     f(x)'  =  0 + 2x  + sec^2 (\frac{\pi x}{2} )\cdot \frac{\pi}{2}

Now

    since 0 =  f^{-1} (4)

We have

      f(0)'  =  0 +  \frac{\pi }{2}  sec^2 (0)

       f(0)'  = \frac{\pi }{2}

Now  

        (f^{-1})'(a) =  \frac{1}{(\frac{\pi}{2} )}

        (f^{-1})'(a) = \frac{2}{\pi }

       

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3 years ago
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