Answer:
The following code is:
do // set do while loop
{
response = stdin.next();
}
while (response != "Y" || response != "y" || response != "N" || response != "n");
// terminate do while loop
Explanation:
The following code starts with do while loop whose variables has already declared and then we assume the availability of the variable "stdin" which references the Scanner object and write some code to execute inside the do-while loop.
Explanation:
Other events at that time are canceled, and the meeting cannot be canceled by the organizer.
The agenda is updated with the user’s contact information, and other events at that time are canceled.
The meeting cannot be canceled by the organizer, and the agenda is updated with the user’s contact information.
The meeting organizer is notified, and a copy of the meeting is added to the user’s Outlook calendar.
<em><u>Answer</u></em>
5 hours
<em><u>Explanation</u></em>
The two working together can finish a job in

Also, working alone, one machine would take one hour longer than the other to complete the same job.
Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.
Their combined rate in terms of x is

This should be equal to 20/9 hours.

Multiply through by;





Factor to get:


It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.
Therefore the slower finish in 5 hours.