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3 years ago

Someone help me with this please

Mathematics

1 answer:

yan [13]3 years ago

4 0

Answer:

hope it helps

plz mark brainliest✌️✌️

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G varies inversely with the square

vivado [14]

Answer:;4.4

Step-by-step explanation: Since it varies inversely we know G times H squared is equal to some constant, k. So we have G*H*H=k. We are told that when H=4, G=.25. Plugging this in, we have .25*4*4=k. This simplifies to 4=k. Our new equation is G*H*H=4. Now, we want to solve for G when H=.3. We plug it in. G*.3*.3=4 => G*.09=4. G=4/.09. This means G is approximately 44.4.

5 0

3 years ago

Read 2 more answers

Fine the missing angle.. x=??

andrew-mc [135]

The opposite angles where two lines cross are called <em>vertical angles.</em><em> </em>

Say it with me: "Vertical angles are congruent!"

Answer: x=100

3 0

3 years ago

Read 2 more answers

Which one please help

rjkz [21]

The answer to your question is B

5 0

3 years ago

A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 10.4

vlabodo [156]

Answer:

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

Step-by-step explanation:

Bernoulli's equation,

$P_1+\frac12 \rho v^2_1+\rho g h_1= P_2+\frac12 \rho v^2_2+\rho g h_2$

P₁ = P₂= atmospheric presser

$\rho$ = density

$\frac12 \rho v^2_1+\rho g h_1= \frac12 \rho v^2_2+\rho g h_2$ [since P₁ = P₂]

$\Rightarrow\rho (\frac12 v^2_1+ g h_1)= \rho(\frac12 v^2_2+ g h_2)$

$\Rightarrow\frac12 v^2_1+ g h_1= \frac12 v^2_2+ g h_2$

$\Rightarrow\frac12 v^2_2-\frac12 v^2_1=g h_1- g h_2$

$\Rightarrow v^2_2- v^2_1=2g h$ [ $h_1-h_2=h$ ]

Here $v_1\approx 0$

$\Rightarrow v^2_2=2g h$

$\therefore v_2=\sqrt {2gh$

Here g= 9.8 m/s² , h = 10.4 m

The velocity of water that leaves from the hole $v_2$ = $\sqrt {2\times 9.8\times 10.4}$ m/s

=14.28 m/s.

Given, the rate of flow from the leak is $2.53\times 10^{-3}$ $m^3/min$

$=\frac{2.53\times 10^{-3}}{60}$ $m^3/s$

Let the diameter of the hole be d.

Then the cross section area of the hole is $=\pi (\frac d2)^2$

We know that,

The rate of flow = Cross section area × speed

$\Rightarrow \frac{2.53\times 10^{-3}}{60} =\pi (\frac d2)^2\times 14.28$

$\Rightarrow (\frac d2)^2=\frac{2.53\times 10^{-3}}{60\times 14.28\times \pi}$

$\Rightarrow d= 1.94 \times 10^{-3}$

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

4 0

3 years ago

How long it takes a 2800 investment to earn $500 interest if it's invested at 7% compounded quarterly. Round to the nearest tent

OleMash [197]

P=present value of investment = 2800
i=interest per quarter=0.07/4=0.0175
n=number of quarters money invested (to be calculated)
Interest = P[(1+i)^n-1]=500
2800((1+0.0175)^n-1)=500
(1+0.0175)^n=500/2800+1
take log on both sides
n(log(1.0175)=log(1+500/2800)
n=log(1+500/2800)/log(1.0175)
=9.471 quarters
=37.88 months
=37.9 months [ nearest tenth of a month ]

4 0

3 years ago