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denis23 [38]
3 years ago
5

There are several external forces that acct on rocks in the rock cycle. Which one is

Biology
2 answers:
zhenek [66]3 years ago
4 0
The answer is B. pressure
mr_godi [17]3 years ago
3 0

Answer:

B) pressure

Explanation:

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(blank) measures how much space matter takes up.
irga5000 [103]

Answer:

volume

Explanation:

it's volume I think

8 0
2 years ago
Which of the following are behavioral adaptions for animals to survive in the extreme cold of the tundra biome?
svp [43]

Answer:

Although habitats provide food, water and shelter that animals need, there is more to survival than just the habitat.

8 0
2 years ago
Read 2 more answers
A student claims that cellular respiration is essential to cells so that they have a means for getting rid of excess carbon diox
Romashka [77]

1. Cellular respiration does not consume carbon dioxide (CO2).

Cellular respiration is a process by which plants produce energy. It consists of anaerobic (without O2) and aerobic phase(with the presence of O2). During the cellular respiration chemical energy derived from the nutrients (like glucose) is transformed into energy molecule adenosine triphosphate (ATP).

2. Unlike photosynthesis, cellular respiration occurs in all eukaryotic organisms (photosynthesis only in plants and some microorganisms). The processes of cellular respiration occur in cytosol (glycolysis) and in the mitochondrion of a cell (Krebs cycle and electron transport chain).


6 0
2 years ago
Read 2 more answers
How is water evaporated around the world
Lady bird [3.3K]
Heat causes evaporation

3 0
2 years ago
HELP ASAP I WILL GIVE BRAINLIST
adelina 88 [10]

Answer:

1) CO₂

2) 0.2551 g

Explanation:

The balanced reactions are:

CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂

1) The gas produced is CO₂.

2) Calculate mass of CaCO₃:

(0.5236 g) (0.4230) = 0.2215 g CaCO₃

Convert to moles:

(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃

Find moles of CaCO₃:

(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂

Convert to mass:

(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂

Calculate mass of MgCO₃:

(0.5236 g) (0.5770) = 0.3021 g MgCO₃

Convert to moles:

(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃

Find moles of MgCO₃:

(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂

Convert to mass:

(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂

Total mass of CO₂:

0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂

8 0
3 years ago
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