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lutik1710 [3]
3 years ago
7

Let x be a positive number such that the distance between x and -3.8 on a number line is exactly 2 times the distance between x

and 1.7. What is the value of x? Express your answer as a decimal to the nearest tenth.
I know the answer is 7.2 but idk why. HELP PLZZ
Mathematics
1 answer:
anyanavicka [17]3 years ago
3 0

Answer:

x = 7.2

Step-by-step explanation:

Let x be a positive number such that the distance between x and -3.8 on a number line is exactly 2 times the distance between x and 1.7.

Now. the distance between - 3.8 and x will be (x + 3.8) and the distance between x and 1.7 will be (x - 1.7) {Since x is a positive number}

(Assuming x is greater than 1.7}

Given that, x + 3.8 = 2(x - 1.7)

⇒ x + 3.8 = 2x - 3.4

⇒ x = 7.2 (Answer)

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siniylev [52]

q(x) =  {x}^{2} + 3x + 4

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

q(a) =  {a}^{2} + 3a + 4

Multiply sides by -2 :

- 2q(a) =  - 2( {a}^{2} + 3a + 4)

- 2q(a) =  - 2 {a}^{2} - 6a - 8

_________________________________

Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

q(a + 1) =  ({a + 1})^{2} + 3(a + 1) + 4 \\

q(a + 1) =  {a}^{2} + 2a + 1 + 3a + 3 + 4 \\

q(a + 1) =  {a}^{2} + 5a + 8

_________________________________

Step (3)

q(a + 1) - 2q(a) =

{a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 =  \\

-  {a}^{2} - a  =  - a(a + 1)

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

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