We will need a picture. If you don't have one then we could possibly tell you the wrong answer and I really don't want that to happen.
For any distribution, the sum of the probabilities of all possible outcomes must be 1. In this case, we have to have
We're told that 
, and we're given other probabilities, so we have
The expected number of calls would be
![E[X]=\displaystyle\sum_xx\,P(X=x)](https://tex.z-dn.net/?f=E%5BX%5D%3D%5Cdisplaystyle%5Csum_xx%5C%2CP%28X%3Dx%29)
![E[X]=0\,P(X=0)+1\,P(X=1)+\cdots+4\,P(X=4)](https://tex.z-dn.net/?f=E%5BX%5D%3D0%5C%2CP%28X%3D0%29%2B1%5C%2CP%28X%3D1%29%2B%5Ccdots%2B4%5C%2CP%28X%3D4%29)
![E[X]=1.4](https://tex.z-dn.net/?f=E%5BX%5D%3D1.4)
Answer:
x^2y^4
Step-by-step explanation:
8 divided by 8 = 1
x divided by x^2 = x
y^3 divided by y = y^2
(xy^2)^2 = x^2y^4
Answer:
The second one.
Step-by-step explanation:
Answer:
C.
Step-by-step explanation:
C.
You can only combine like terms on the same side of the equals sign.
