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UNO [17]
3 years ago
9

Checks are stale dated when

Mathematics
2 answers:
lys-0071 [83]3 years ago
5 0
<span>it was written more than six months prior to being presented to a bank or other financial institution.</span>
lina2011 [118]3 years ago
4 0
My guess is before the current date but not sure hope that helped and sorry I could not do more and always good luck
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What is the equation of the line that passes through the point (-2,2) and (0,5)? A. Y=-3/2x+5 B.Y=x-5 C.Y=3/2x+5 D. Y=x+5
Bond [772]
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sergij07 [2.7K]
Ask your teacher hfjsjcnjensjte
4 0
2 years ago
Help as soon as possible please
marta [7]

(3x + 5)° + (10x - 7)° = 180°

13x + (-2) = 180

13x = 180 + 2

13x = 182

x = 14

∠QRT = 3 * 14 + 5 = 42 + 5 = 47°

∠TRS = 10 * 14 - 7 = 140 - 7 = 133°

6 0
3 years ago
A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet
Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

L_{1} = 2W_{1}

Also, the area of the walkway of 2 feet wide is 448:

W_{2} = 2 ft

A_{T} = W_{2}*L_{2} = 448 ft^{2}

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

A_{T} = A_{1} + A_{w}    (1)          

The area of the pool is given by:

A_{1} = L_{1}*W_{1}        

A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}  (2)          

And the area of the walkway is:

A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}    (3)          

Where the length of the bigger rectangle is related to the lower rectangle as follows:                  

L_{2} = 4 + L_{1} = 4 + 2W_{1}   (4)        

By entering equations (4), (3), and (2) into equation (1) we have:

A_{T} = A_{1} + A_{w}

A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}                

448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}            

224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}

224 = W_{1}^{2} + 8 + 6W_{1}

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

L_{1} = 2W_{1} = 2*12 ft = 24 ft

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!                                                                                          

8 0
2 years ago
Which of the following expressions is a polynomial?
Cloud [144]
Polynomial requirements
1. never divide by a placeholder
2. variable exponent has to be a whole number
3. can't have infinte terms


by 1. we eliinate 2nd one

by 2. we eliminate first one (√x=x^1/2) and 3rd one because it has an exponent in placeholder

thie leaves us with last one
f(x)=2x³-5x⁵-(2/9)x²+9


last one is answer
5 0
3 years ago
Read 2 more answers
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