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Romashka-Z-Leto [24]
3 years ago
10

In the problem 4x + 10 list a term, factor, coefficient, and constant.​

Mathematics
1 answer:
kifflom [539]3 years ago
6 0

term- 4x and 10

This is because to be a term it has to be + or -

Factor- 4x+10

This is because that is what is happening in the problem

Coefficient- 4y

I don't know what the constant would be, But I hope that this helps you

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3/4=j-1/2 solve the equation check your solution
DIA [1.3K]
3/4= j-1/2
first to add 1/2 to both sides to solve for j 
3/4 + 1/2= j
second you find a common denominator in order to add 3/4 and 1/2, the common denominator would be 4, you would have to change 3/4 at all because the denominator is already 4 but in order to make the denominator of 1/2, 4 you would have to multiply both the denominator and numerator by 2 so 
3/4 + 2/4 = 5/4
so 5/4 =j

to check your answer you plug 5/4 in for j 
3/4 = 5/4 -1/2
again you need to find a common denominator between 5/4 and 1/2 which again would be 4, and again you wouldn't change 5/4 but you would multiply both the numerator and the denominator of 1/2 so 
3/4= 5/4-2/4
5-2= 3 and you would keep the 4 so 
5/4 - 2/4 = 3/4

so j =  5/4
5 0
3 years ago
I suck at math so can you help with this is a test so Yh
vekshin1
The correct answer is option D:)
3 0
2 years ago
What are the points
Goryan [66]

Answer:

There are 9 dots. So 9.

Step-by-step explanation:

Just take my word for it.

7 0
3 years ago
Find the volume of the sphere. leave your answer in terms of pi <br>r=4​
cricket20 [7]

Answer:

To find an answer in pi square the radius and multiply by pi

Step-by-step explanation:

To

find volume of a sphere = 4/3Πr³

Answer =17,164.2pi Am not sure but i hope its correct.

4 0
2 years ago
I need help on a overdue math homework please.
Annette [7]

how come you need help? It is super easy. Just combine Like Terms.

https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-expressions-and-variables/cc-6th-combining-like-terms/v/combining-like-terms-1

That is a website for help!

8 0
3 years ago
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