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Elden [556K]
2 years ago
6

After breaking your penny bank, you notice that you have $4.87 in quarters ($0.25), dimes ($0.10), nickels ($0.05), and pennies

($0.01). If there are twice as many pennies as nickels and one and a half time the number of nickels as dimes and 34 more pennies than quarters, how many pennies do you have? A. 17 B. 34 C. 42 D. 44
Mathematics
1 answer:
ira [324]2 years ago
3 0

Answer: Option 'c' is correct.

Step-by-step explanation:

Let the number of dimes  be 'x'.

Let the number of nickels  be '\dfrac{3}{2}x'.

Let the number of pennies be \dfrac{3}{2}\times 2x=3x

Let the number of quarters be '3x-34'.

As we know that

1 quarter = $0.25

1 dime = $0.10

1 nickel = $0.05

1 penny = $0.01

According to question, we get that

0.10x+0.05\times \dfrac{3x}{2}+0.01\times 3x+0.25(3x-34)=4.87\\\\0.10x+0.075x+0.03x+0.75x-8.5=4.87\\\\\\0.955x=4.87+8.5\\\\0.955x=13.37\\\\x=\dfrac{13.37}{0.955}\\\\x=14

So, the number of pennies is given by

3x=3\times 14=42

Hence, Option 'c' is correct.

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Leona [35]
Combine like terms.


7g + 4g + 3g + g = 15g

15g - 13g = 2g


2g = 10


Divide by 2 on both sides.


g = 5
5 0
3 years ago
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salantis [7]

Answer:

B


Step-by-step explanation:


4 0
3 years ago
Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance
a_sh-v [17]

Answer:

i. When the temperature is above 616.712^{o}F, it changes to gas.

ii. When the temperature is below -33.052^{o}F, it changes to solid.

Step-by-step explanation:

Matter generally exists in either a solid, liquid or gaseous form. With each phase having a certain range of temperature.

Temperature scale of a given substance can be either in Celsius, Fahrenheit or Kelvin. And conversion from one scale to another can be achieved. Example, Celsius scale can be converted to Fahrenheit by:

F = \frac{9}{5} θ + 32

where: F is the equivalent temperature in Fahrenheit, θ is the value of temperature in degree Celsius.

Given that: melting point of the substance = -36.14^{o}C

⇒ F =  \frac{9}{5} x -36.14^{o} + 32

      = -33.052^{o}F

The boiling point = 324.84^{o}C

F =  \frac{9}{5} x  324.84^{o} + 32

  = 616.712^{o}F

The melting point of the substance is -33.052^{o}F, and boiling point is 616.712^{o}F.

Therefore, the range of temperatures for which the substance is not in a liquid state are:

i. When the temperature is above 616.712^{o}F, it changes to gas.

ii. When the temperature is below -33.052^{o}F, it changes to solid.

3 0
3 years ago
A lollipop has a radius of 15m. Determine the diameter, circumference, and area of the lollipop.
Leokris [45]
The answers are:

Diameter: 30m
Circumference: 94.24777960769379
Area: 706.8583470577 m<span>2

I hope this helps you. Good luck with your work!</span>
6 0
3 years ago
Listed below are the weights in pounds of 11 players randomly selected from the roster of the Seattle Sea-hawks when they won Su
weeeeeb [17]

Answer:

No. These measures show a thinner team of NFL players according to the mean, variance, standard deviation, and quartiles.

Step-by-step explanation:

1) The measures of variation, namely The Range, Variance, Quartiles, Interquartiles, Sum of Squares, etc. shows us how the data are dispersed.

The Range Δ is calculated:

\Delta =305-189=116 Maximum value - Minimum value for weight

Mean:

\bar{x}=\frac{189+254+235+225+190+305+202+190+252+305}{11}\approx 231.09 \:pounds

Variance:

s^{2}=\frac{\sum_{i=1}^{n} (x_i-\bar{x})^{2}}{n-1}\Rightarrow s=1923.69\\

The Standard Deviation of the sample

s=\sqrt{s^{^{2}}}\Rightarrow s\approx 43.86\\

2) Since there is no preceding exercise, the comparison was made to a recent study in which a NFL player average weight is about 245 pounds (average),

Since 25% of this list are player whose weight is 192.5 lbs and 50% (2nd Quartile) =225 lbs , finally only at the 3rd Quartile we have players above the regular NFL average with 253. This, added with the other data, allow us to say that this list is not a typical of all NFL players.

4 0
3 years ago
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