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zaharov [31]
3 years ago
9

Find the inverse function of h(x)=-2/3x+6

Mathematics
1 answer:
storchak [24]3 years ago
7 0

Answer:

-3/2 (x - 6)

Step-by-step explanation:

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Use the net as an aid to compute the surface area of a triangle pyramid with an equilateral triangle base
murzikaleks [220]

Answer:

106 ft 2

Step-by-step explanation:

6 0
3 years ago
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x + 3y = 7 x - 3y = 1 Solve the system of equations. A) x = 4, y = 1 B) x = 1, y = 4 C) x = - 2 3 , y = 3 D) x = 3, y = - 2 3
Alik [6]
X+3y=7
x-3y=1
add them together

x+3y=7
<u>x-3y=1 +
</u>2x+0y=8

2x=8
divide 2
x=4
subsitute
x+3y=7
4+3y=7
subtract 4
3y=3
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4 years ago
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I need help on saxon math algebra 1 lessons 36-40 can you please help me ,
saul85 [17]
36-40= -4
36 subtracted by 40 equals negative 4
-4
7 0
3 years ago
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A line passes through (2, –1) and (8, 4). a. Write an equation for the line in point-slope form. b. Rewrite the equation in stan
pentagon [3]
The point-slope form of a line is:

y-y1=m(x-x1),  where m=slope and (x1,y1) is any point on the line

First we need to find the slope, which is (y2-y1)/(x2-x1)

m=(4--1)/(8-2)

m=5/6 and we can use either point, I'll use (8,4)

y-4=(5/6)(x-8)

That is your equation in point-slope form.

Now the standard equation of a line is ax+by=c

y-4=(5/6)(x-8)  we can perform the indicated multiplication on the right side

y-4=(5x-40)/6  multiply both sides by 6

6y-24=5x-40  add 24 to both sides

6y=5x-16  subtract 5x from both sides

-5x+6y=-16  and by convention, the standard equation of a line should be expressed with a positive coefficient for x, so multiply both sides by -1

5x-6y=16
8 0
3 years ago
Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }

Note that

\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}

When dividing \sqrt[7]{x^5} by \sqrt[4]{x^2}, we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}

and the result is x^{\frac{3}{14}}=\sqrt[14]{x^3}

2. Given equation 3\sqrt[4]{(x-2)^3} -4=20

Add 4:

3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24

Divide by 3:

\sqrt[4]{(x-2)^3} =8

Rewrite the equation as:

(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3

Hence,

\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18

3 0
3 years ago
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