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OleMash [197]
4 years ago
5

HELP LAST QUESTION I NEED IT AND I WILL MARK BRAINLEST IF RIGHT

Mathematics
2 answers:
galben [10]4 years ago
6 0
The answer is b

There is no solution to the problem because it just doesn’t make sense. You can not add to sides with so many variables and expect to get a answer
3241004551 [841]4 years ago
3 0
The answer for this question is B
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I NEED HELP PLEASE, THANKS!
Finger [1]

Answer:

the 3rd option is the answer

Step-by-step explanation:

I hope the attached file is self-explanatory

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3 years ago
In the right ΔABC, AN is the altitude to the hypotenuse. Find BN, AN, and AC, if AB=2√5 in and NC= 1 in.
kipiarov [429]

Answer:

BN=4\ \text{in}

AN=2\ \text{in}

AC=\sqrt{5}\ \text{in}

Step-by-step explanation:

Let BN=x

BC=c

NC=y=1\ \text{in}

AB=a=2\sqrt{5}\ \text{in}

AC=b

We have the relation

\dfrac{BC}{AB}=\dfrac{AB}{BN}\\\Rightarrow \dfrac{c}{a}=\dfrac{a}{x}\\\Rightarrow c=\dfrac{a^2}{x}\\\Rightarrow x+1=\dfrac{a^2}{x}\\\Rightarrow x^2+x=20\\\Rightarrow x^2+x-20=0\\\Rightarrow x=\frac{-1\pm \sqrt{1^2-4\times 1\times \left(-20\right)}}{2\times 1}\\\Rightarrow x=4,-5

\boldsymbol{BN=4\ \text{in}}

h=\sqrt{a^2-x^2}\\\Rightarrow h=\sqrt{(2\sqrt{5})^2-4^2}\\\Rightarrow h=2\ \text{in}

\boldsymbol{AN=2\ \text{in}}

b=\sqrt{h^2+y^2}\\\Rightarrow b=\sqrt{2^2+1^2}\\\Rightarrow b=\sqrt{5}\ \text{in}

\boldsymbol{AC=\sqrt{5}\ \text{in}}

8 0
3 years ago
If the area of a rectangle is w^2 - 8w - 9, which of the following could be the side length of the rectangle?
lorasvet [3.4K]

Answer:

w+8 is the length of rectangle

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3 years ago
Dentify the type of variation given and the constant of variation (k)
velikii [3]
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4 years ago
What is 4+2(5)+(-3)=
Pavel [41]

Answer:

The answer is 11, I think, hope this helps!

Step-by-step explanation:

4 0
3 years ago
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