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frozen [14]
3 years ago
9

Find the value of x to the nearest tenth.

Mathematics
2 answers:
Leona [35]3 years ago
8 0

Answer:

x = 9

Step-by-step explanation:

Given : A triangle with angle 39 degree.

To find : Find the value of x to the nearest tenth.

Solution : We have given

A triangle with angle 39 degree and hypotenuse = x.

Adjacent side = 7 .

Cos(theta) = \frac{Adjacent}{Hypotenuse}.

Plug the values

Theta = 39 degree.

Cos(39) = \frac{7}{x}.

x = \frac{0.777}{7}.

x = 9.09

Nearest tenth is 9.09

Therefore, x = 9

rosijanka [135]3 years ago
3 0
Check the picture below

the angle is in degrees, thus, make sure your calculator is in Degree mode

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Answer:

-3 / 5

Step-by-step explanation:

18-6 / -16-4

12 / -16-4

12 / -20

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Find the value of 5x - 4x^2 for x=2
photoshop1234 [79]

Answer:

=10

Step-by-step explanation:

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5(2)-4(2)²

=10-0

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if $5,000,000 isinvested at 4% interest compunded continuously, how much willl the investment be worth in 30 years
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8 0
3 years ago
Find the distance between two points ( -1,1) and (2,-4)
sladkih [1.3K]

Answer:

The distance between two points ( -1,1) and (2,-4) is:

d=\sqrt{34}  or d = 5.8 units.

Step-by-step explanation:

Given the points

  • (-1, 1)
  • (2, -4)

Finding the distance between (-1, 1) and (2, -4) using the formula

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

substitute (x₁, y₁) =  (-1, 1)   and  (x₂, y₂) = (2, -4)

   =\sqrt{\left(2-\left(-1\right)\right)^2+\left(-4-1\right)^2}

   =\sqrt{\left(2+1\right)^2+\left(-4-1\right)^2}

   =\sqrt{3^2+5^2}

   =\sqrt{9+25}

   =\sqrt{34}  units

or

d = 5.8 units

Therefore, the distance between two points ( -1,1) and (2,-4) is:

d=\sqrt{34}  or d = 5.8 units.

3 0
3 years ago
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