2 tens, and 8 ones. I say this because 20 = 10 + 10 so, two tens. 8= 1+1+1+1+1+1+1+1 so, eight ones.
Answer:
The graph below.
I know it might not be correct but I hope it helps somewhat!
Answer:
395, 17.212
(360.576,429.424)
Step-by-step explanation:
Given that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p.
Here 
Since np and nq are greater than 5 by rule of thumb we can approximate binomial to normal.
Mean = np = 395
Variance = npq = 
Std dev = 17.212
Thus X no of successes is N(395, 17.212)
THe the minimum usual value mu minus 2 sigma and the maximum usual value mu plus 2 sigma would be

Hello there,
Since one third eggs hatched, 1/3=2eggs. In order to find the total amount off eggs, 1/3+1/3+1/3:2+2+2=6.
Hope this helps!!