Hello from MrBillDoesMath!
Answer:
31a. 2 real roots
31b 2 complex roots
Discussion:
31a.
2x^2 + 3x - 6 = 0
Using standard quadratic notation, the above equation has a = 2, b = 3 and c = -6. The discriminant is given by b^2 - 4ac, which is
3^2 - 4*2*(-6) = 9 + 48 = 57 > 0, so the quadratic has 2 real roots
31b.
The equation is equivalent to 16x^2 + 10x +3 = 0. Its discriminant is
10^2 - 4 * (16) * (3) = 100 - 192 = -92 so this equation has two complex roots
Regards,
MrB
Answer:
radius ≈ 15.5
Step-by-step explanation:
the radius is RS
the angle between a tangent and the radius at the point of contact is 90°
then Δ RST is a right triangle
using Pythagoras' identity in the right triangle.
the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , then
RS² + ST² = RT² ( substitute values )
RS² + 7² = 17²
RS² + 49 = 289 ( subtract 49 from both sides )
RS² = 240 ( take square root of both sides )
RS =
≈ 15.5 ( to 1 dec. place )
Answer:
The measure of each side of the cube is
<h2>15 inches</h2>
Step-by-step explanation:
Since it's a cube all it's sides are equal
To find the length of each side we use the formula
Volume of a cube = l³
where l is the measure of one side
From the question
Volume = 3375 cubic inches
Substitute this value into the formula and solve for l
That's
<h3>

</h3>
Find the cube root of both sides
That's
<h3>
![\sqrt[3]{ {l}^{3} } = \sqrt[3]{3375}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%7Bl%7D%5E%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B3375%7D%20)
</h3>
We have the final answer as
<h3>l = 15 inches</h3>
Hope this helps you
Your answer will be 60%
Have a nice day
Answer:
Step-by-step explanation:
First, make sure you know which section of the number line you want as 1 and 2. Next, put 0.25 not right at 0 but very close, then put 0.75 farther but not too much from 0.25. Then for the decimal 1.99 put that very close to where you marked the 2 but, not on the 2. Finally, put 2.03 very close to 2 but not exactly on the 2. Also, make sure that the number line is marked evenly.