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Kipish [7]
3 years ago
11

My dad was painting our living room. He started with 5/9 of a can of paint.

Mathematics
1 answer:
SpyIntel [72]3 years ago
8 0

Answer:

0.2 rounded up or 1/5 (also rounded up)

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7 more inches to be a foot tall

Step-by-step explanation:

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A painting without its frame has a width 2.5 times its height, h, in inches. Its frame is 3 in. wide all along its perimeter. Wh
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Answer:

You will not be able to find the area of the framed painting without finding the length, which you did not provide. Assuming you meant “3 inches wide” to actually mean the length then the surface area of the painting is 9 inches squared. However, to find the height, you must divide 3 by 2.5 as the width was said to be 2.5 times the height of the painting. This will give you an answer of 1.2 inches in height.
7 0
3 years ago
I need the answer ASAP! Please help me!
masha68 [24]

Answer:

Please check the explanation.

Step-by-step explanation:

<u>Determining the length of BC</u>

From the diagram, it is clear that

  • The point B is located at (-8, 10) and point C is located at (8, 10)

Since points A and C are located on a horizontal straight line. Thus, the length of BC can be determined by counting the x-axis units from reaching x = -8 to x = 8. i.e. 8-(-8) = 8+8 = 16

Thus, the length of BC = 16 units

<u>Determining the length of CD</u>

Given

  • C (8, 10)
  • D (2, -2)

The distance between C(8, 10) and D(2, -2)

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

CD=\sqrt{\left(2-8\right)^2+\left(-2-10\right)^2}

      =\sqrt{6^2+12^2}

      =\sqrt{36+144}

      =\sqrt{180}

      =\sqrt{36\times 5}

      =6\sqrt{5}

Thus, the length of CD =6\sqrt{5} units

<u>Determining the length of ED</u>

Given

  • E (-8, -4)
  • D (2, -2)

The distance between E(-8, -4) and D(2, -2)

ED=\sqrt{\left(2-\left(-8\right)\right)^2+\left(-2-\left(-4\right)\right)^2}

      =\sqrt{10^2+2^2}

      =\sqrt{100+4}

      =\sqrt{104}

       =\sqrt{26\times \:4}

        =2\sqrt{26}

Thus, the length of ED =2\sqrt{26} units

<u>Determining the length of EB</u>

From the diagram, it is clear that

  • The point E is located at (-8, -4) and the point B is located at (-8, 10)

Since points E and B are located on a vertical straight line. Thus, the length of EB can be determined by counting the y-axis units from reaching y = -4 to y = 10. i.e. 10-(-4) = 10+4 = 14

Thus, the length of EB = 14 units

4 0
3 years ago
Ok i need a real math expert to help me with 1,2,or3 questions consider it a challenge diet one to answer gets thanked and is ma
Ber [7]

Step-by-step explanation:

(picture explains)

Hope this helps!

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Find the equation of the linear function represented by the table below in slope-
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Y= x+4 is the answer
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