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AnnyKZ [126]
3 years ago
13

If you had access to all resources, how would you deal with a hard drive that had not been formatted?

Computers and Technology
1 answer:
BaLLatris [955]3 years ago
7 0

Answer:

format the hard drive using the mother board bios!!

Explanation:

i have done this lol

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Literally just do a colon and parenthesis :(

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Read 2 more answers
Create a program in c/c++ which accepts user input of a decimal number in the range of 1 -100. Each binary bit of this number wi
kirill115 [55]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

void switch_fun(int input)

{

//array to store binary of input number

   int bin[7];

   // convert the number into binary

   for(int i=0; input>0; i++)

       {

           bin[i]=input%2;

           input= input/2;

       }

   // print the switch number and their status

   cout<<"Switch number:\t 1\t 2\t 3\t 4\t 5\t 6\t 7 \n";

   cout<<"status:      ";

   for(int j=6;j>=0;j--)

   {

   // if bit is 1 print "ON" else print "OFF"

       if(bin[j]==1)

           cout<<"\t ON";

       else

           cout<<"\t OFF";

   }

}

int main()

{

   int n;

   cout<<"enter the number between 1-100 only:");

   // read a number in decimal

   cin>>n

   // validate the input

   while(n<1 ||n>100)

   {

     cout<<"wrong input!! Input must be in between 1-100:"<<endl;

     cout<<"enter the number again :";

     cin>>n;

   }

// call the function with input parameter

  switch_fun(n);

return 0;

}

Explanation:

Read a decimal number from user. If the number is not between 1 to 100 the it will again ask user to enter the number until the input is in between 1-100.Then it will call the fun() with parameter n. First it will convert the decimal to binary array of size 7.Then print the status of switch.If bit is 1 then print "ON" else it will print "OFF".

Output:

enter the number between 1-100 only:-5

wrong input!! Input must be in between 1-100:

enter the number again :125

wrong input!! Input must be in between 1-100:

enter the number again :45

Switch number:   1       2       3       4       5       6       7

Status:          OFF     ON      OFF     ON      ON      OFF     ON

8 0
3 years ago
Design and implement a class dayType that implements the day of the week in a program. The class dayType should store the day, s
Afina-wow [57]

The code is implemented based on the given operations.

Explanation:

#include <iostream>

#include <string>

using namespace std;

class dayType

{ private:

 string day[7];

 string presentDay;

 int numofDays;

public:

 void setDay(string freshDay);

 void printDay() const;

 int showDay(int &day);

 int nextDay(int day);

 int prevDay(int day) const;

 int calcDay(int day, int numofDays);    

 dayType()

 {

  day[0] = "Sunday";

  day[1] = "Monday";

  day[2] = "Tuesday";

  day[3] = "Wednesday";

  day[4] = "Thursday";

  day[5] = "Friday";

  day[6] = "Saturday";

  presentDay = day[0];

  numofDays = 0;

 };

 ~dayType();

};

#endif

#include "dayType.h"

void dayType::setDay(string freshDay)

{

  presentDay = freshDay;

}

void dayType::printDay()

{

  cout << "Day chosen is " << presentDay << endl;

}

int dayType::showDay(int& day)

{

  return day;

}

int dayType::nextDay(int day)

{

day = day++;

if (day > 6)

 day = day % 7;

switch (day)

{

case 0: cout << "The successive day is Sunday";

 break;

case 1: cout << "The successive day is Monday";

 break;

case 2: cout << "The successive day is Tuesday";

 break;

case 3: cout << "The successive day is Wednesday";

 break;

case 4: cout << "The successive day is Thursday";

 break;

case 5: cout << "The successive day is Friday";

 break;

case 6: cout << "The successive day is Saturday";

 break;

}

cout << endl;

return day;

}

 

int dayType::prevDay(int day)

{

day = day--;

switch (day)

{

case -1: cout << "The before day is Saturday.";

 break;

case 0: cout << "The before day is Saturday.";

 break;

case 1: cout << "The before day is Saturday.";

 break;

case 2: cout << "The before day is Saturday.";

 break;

case 3: cout << "The before day is Saturday.";

 break;

case 4: cout << "The before day is Saturday.";

 break;

case 5: cout << "The before day is Saturday.";

 break;

default: cout << "The before day is Saturday.";

}

cout << endl;

return day;

}

int dayType::calcDay(int addDays, int numofDays)

{

addDay = addDays + numofDays;

if (addDay > 6)

 addDay = addDay % 7;

switch(addDay)

{

case 0: cout << "The processed day is Sunday.";

 break;

case 1: cout << "The processedday is Monday.";

 break;

case 2: cout << "The processedday is Tuesday.";

 break;

case 3: cout << "The processedday is Wednesday.";

 break;

case 4: cout << "The processedday is Thursday.";

 break;

case 5: cout << "The processedday is Friday.";

 break;

case 6: cout << "The processedday is Saturday.";

 break;

default: cout << "Not valid choice.";

}

cout << endl;

return addDays;

}

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