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masya89 [10]
3 years ago
7

Image 1image 2image 3none ​

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
3 0

Answer:

Image 1

Step-by-step explanation:

It has a varitiy of differnt circles, while the others only have one kind of circle.

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What number is divisible by 2,3 and 6
UkoKoshka [18]
I believe it’s 12 but i could be wrong
8 0
3 years ago
Read 2 more answers
What does the digit 6 represent in ?
marshall27 [118]

Answer:

6 is in ten place and its place value is 60, 3 is in ones place and its place value is 3.

4 0
3 years ago
In a chess tournament, each player plays every other player exactly once. If it is known that 105 games were played, how many pl
diamong [38]

Answer:

15 players played in the chess tournament.

Step-by-step explanation:

When there are 15 players, the first player plays 14 games and step aside.

remaining 14 player

next player plays 13 games. steps aside

remaining 13 players

next player plays 12 games. steps aside

remaining 12 players

next player plays 11 games. steps aside

remaining 11 players

.

.

.

.

Last player plays 1 game and steps aside

remaining 1 player who will not play against himself.

∴ Sum of all games played

= 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 105 games played

3 0
4 years ago
3/4 yard long and 1/2 yard tall what is the area of the poster frame
zmey [24]
The area is 3/8 yd².

Area = length x width

Given:
length = 3/4 yard
width = 1/2 yard

Area = 3/4 yd * 1/2 yd
Area = 3*1/4*2
Area = 3/8 yd²

In multiplying fractions, multiply the numerators, then, multiply the denominators. lastly, simplify the fraction. 3/8 yd² is already in its simplest form.
3 0
4 years ago
Read 2 more answers
This may prove to be somewhat tricky.) Suppose that we have 10 coins, which are weighted so thatwhen flipped theith coin shows h
timama [110]

Answer:

2/10

Step-by-step explanation:

Probability of getting head on i'th coin = i/10

Probability Pr of getting head on 2nd coin (Event A) = 2 / 10

Probability Pr of getting head on 1st coin (Event B) = 1/10

Probability A given B = Pr (A/B) = Pr (A∩B) / Pr B ;

where A∩B = Pr (A & B) = Pr A X Pr B

Putting in above formula :

Pr (A/B) = <u>[(</u>1/10)x(2/10<u>)]</u>  / 1/10

= 2/10

4 0
4 years ago
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