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3 years ago

Rewrite number without radicals or exponents

Mathematics

1 answer:

Sonbull [250]3 years ago

8 0

32/243

Hmm at least twenty characters. What should I type?

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Please help me ASAP

Rama09 [41]

Answer:

Step-by-step explanation:

6(6+x) = 5(5+x+3)

36+6x = 25+5x+15

6x-5x=40-36

x=4

6 0

3 years ago

Read 2 more answers

A location in space is the definition of a

elena-14-01-66 [18.8K]

A location in space is the definition of a Point.

4 0

3 years ago

Is (-5, -8) a solution of y > 3x +6?

andreev551 [17]

Answer:

Yes

Step-by-step explanation:

y>3x+6 creates this graph:

Where (-5,-8) is in the shaded area

7 0

3 years ago

1)What is the mass of Nitrogen in NH3? (use two decimal places)

Mars2501 [29]

Answer:

1) The Mass of Nitrogen in $NH_3$ is 14.00 gm.

2) The Mass of Hydrogen in $NH_3$ is 3.00 gm.

3)The Molar Mass of $NH_3$ is 17.00 gm.

Step-by-step explanation:

Solving for Part 1.

In $NH_3$ that is Ammonia there is 1 atom of Nitrogen.

So the atomic mass of Nitrogen is same as the mass of Nitrogen in $NH_3$ .

Atomic mass of Nitrogen = 14.00 gm

Hence The Mass of Nitrogen in $NH_3$ is 14.00 gm.

Solving for Part 2.

In $NH_3$ there are 3 atoms of Hydrogen.

Atomic mass of Hydrogen = 1.00 gm

So the mass of Hydrogen in $NH_3$ is 3 times of its atomic mass.

Mass of Hydrogen = 3 × Atomic mass of Hydrogen

$Mass\ of\ Hydrogen =3\times1.00=3.00\ gm$

Hence The Mass of Hydrogen in $NH_3$ is 3.00 gm.

Solving for Part 3.

In $NH_3$ there is 1 atom Nitrogen and 3 atoms of Hydrogen.

So molar mass is the sum of mass of nitrogen and mass of Hydrogen in $NH_3$ .

Molar mass of $NH_3$ =Mass of Nitrogen+Mass of Hydrogen

$Molar\ mass\ of\ NH_3=14.00+3.00=17.00\ gm$

Hence The Molar Mass of $NH_3$ is 17.00 gm.

6 0

3 years ago

A farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. No fencing is needed along the bar

Zina [86]

Answer:

The dimensions for the plot that would enclose the most area are as follows:

Width = 116.67 ft

Length = 175 ft.

Step-by-step explanation:

Note: Kindly refer to the attached diagram where:

x = Length of the rectangular area

y = Width of the rectangular area.

The fencing along the west side of the plot is shared with a neighbor who will split the cost of that portion of the fence. This implies that it is $10 per foot. Otherwise, it will be $20 per foot. Since no fencing is needed along the barn, it implies that there is no fence along the northern length.

Since the farmer is not willing to spend more than $7000, we have:

10y + 20x + 20y = 7000

20x + 30y = 7000

Divide through by 20, we have:

x + 1.5y = 350

x = 350 - 1.5y …………………………. (1)

The fenced area is

A = x * y ………………………………….. (2)

Substituting equation (1) into (2), we have:

A = (350 - 1.5y)y

A = 350y - 1.5y^2 ……………. (3)

To maximize A, equation (3) is differentiated with respect to y and equated it to 0 as follows:

That is,

A'(y) = 350 - 3y = 0

Solving for y, we have:

y = 350/3

y = 116.67 ft

Substituting y = 116.67 for y in equation (1), we have:

x = 350 - (1.5 * 116.67)

x = 175ft

Therefore, the dimensions for the plot that would enclose the most area are as follows:

Width = 116.67 ft

Length = 175 ft.

3 0

3 years ago