In a group of students, 30 played chess, 19 played volleyball, 25 played
1 answer:
Answer:
Explained below.
Step-by-step explanation:
Denote the events as follows:
<em>C</em> = chess
<em>V</em> = volleyball
<em>B</em> = basketball
The data provided is as follows:
n (C) = 30
n (V) = 19
n (B) = 25
n (C ∩ V) = 14
n (B ∩ V) = 8
n (B ∩ C) = 15
n (C ∩ V ∩ B) = 5
Consider the Venn diagram below.
The number of students who played only chess is marked in pink:
n (Only C) = 6
The number of students who played only volleyball is marked in blue:
n (Only V) = 2
The number of students who played only basketball is marked in orange:
n (Only B) = 7
The number of students who played all three is marked in grey:
n (C ∩ V ∩ B) = 5
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Answer:
x=2.125
y=0
C=19.125
Step-by-step explanation:
To solve this problem we can use a graphical method, we start first noticing the restrictions and
, which restricts the solution to be in the positive quadrant. Then we plot the first restriction
shown in purple, then we can plot the second one
shown in the second plot in green.
The intersection of all three restrictions is plotted in white on the third plot. The intersection points are also marked.
So restrictions intersect on (0,0), (0,1.7) and (2.215,0). Replacing these coordinates on the objective function we get C=0, C=11.9, and C=19.125 respectively. So The function is maximized at (2.215,0) with C=19.125.
