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OleMash [197]
3 years ago
6

In a group of students, 30 played chess, 19 played volleyball, 25 played

Mathematics
1 answer:
saul85 [17]3 years ago
5 0

Answer:

Explained below.

Step-by-step explanation:

Denote the events as follows:

<em>C</em> = chess

<em>V</em> = volleyball

<em>B</em> = basketball

The data provided is as follows:

n (C) = 30

n (V) = 19

n (B) = 25

n (C ∩ V) = 14

n (B ∩ V) = 8

n (B ∩ C) = 15

n (C ∩ V ∩ B) = 5

Consider the Venn diagram below.

The number of students who played only chess is marked in pink:

n (Only C) = 6

The number of students who played only volleyball is marked in blue:

n (Only V) = 2

The number of students who played only basketball is marked in orange:

n (Only B) = 7

The number of students who played all three is marked in grey:

n (C ∩ V ∩ B) = 5

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PLZ HELP ME DO THIS ITS DUE RN
Ostrovityanka [42]

Answer:

least to greatest: -5 and 1

Step-by-step explanation:

they represent the zeroes of the function and are sorted from least to greatest

8 0
3 years ago
EasyElectrics supermarket orders light bulbs from suppliers, AA Electronics and AAA Electronics. EasyElectrics purchases 30% of
saw5 [17]

Answer: (a) 0.006

               (b) 0.027

Step-by-step explanation:

Given : P(AA) = 0.3 and P(AAA) = 0.70

Let event that a bulb is defective be denoted by D and not defective be D';

Conditional probabilities given are :

P(D/AA) = 0.02 and P(D/AAA) = 0.03

Thus P(D'/AA) = 1 - 0.02 = 0.98

and P(D'/AAA) = 1 - 0.03 = 0.97

(a) P(bulb from AA and defective) = P ( AA and D)

                                                       = P(AA) x P(D/AA)

                                                       = 0.3 x 0.02 = 0.006

(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)

                         = P(AA) x P(D/AA) + P(AAA) x P(D/AAA)

                         = 0.3(0.02) + 0.70(0.03)

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3 0
3 years ago
Can any kind soul help me ASAP!​
CaHeK987 [17]

Answer:

Hope it helps u

Step-by-step explanation:

As we know that ,

Mean = sum of the terms/ numbers of terms

But here grouped data is given so , we use the formula

Mean=∑[f. m]/ ∑f

where f is frequency and m is mid point of each height ,

Now first we have to find the mid point of each interval, where

midpoint of each interval = (lower boundary + upper boundary)/2

m1=(150+154)/2 = 152

m2=(155+159)/2= 157,now found other by same formula, for each interval

m3= 162

m4= 167

m5=172    Now we find the midpoint of each interval ,so now

∑[f. m]=f1*m1+f2*m2+f3*m3+f4*m4+f5*m5

now putting the values of each frequency for given interval and midpoint of each interval we will get,

∑[f. m]=456+942+1296+167*x+344 = 167*x+3038

Now find,

∑f=f1+f2+f3+f4+f5

∑f=19+x

Now we have,

∑[f. m]=167*x+3038

∑f=19+x

also given mean height=161.6 cm

putt these values in above equation we get,

161.6=\frac{167*x+3038}{19+x}

now solve this ,

161.6(19+x)=167*x+3038

3070.4+161.6*x=167*x+3038

3070.4-3038=167*x-161.6*x

32.4=5.4*x

x=32.4/5.4

<h2>x=6   Ans........</h2>

3 0
3 years ago
-2 - 6
Tatiana [17]

Answer:

-8

4

-15

-8

7

42

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15

-9

-12

Step-by-step explanation:

-2 - 6 = -8

8 + (-4) = 4

10 + (-25) = -15

-15 - (-7) = -8

-6 - (-13) = 7

-7 x -6 = 42

-12 x 5 = -60

60/4 = 15

72/-8 = -9

48/-4 = -12

6 0
3 years ago
Find the slope of the line passing through the points and .
sergejj [24]

Answer:

slope = - \frac{7}{5}

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (3, 4 ) and (x₂, y₂ ) = (8, - 3 )

m = \frac{-3-4}{8-3} = \frac{-7}{5} = - \frac{7}{5}

6 0
2 years ago
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