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3 years ago

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PLEASEEEE HELP, I REALLY NEED IT. I WILL MARK BRAINLIEST AND 15 POINTS!!!!!!!! PLEASE HELP. MOST DETAILED GETS BRAINLIEST

1 answer:

Law Incorporation [45]3 years ago

7 0

I dot plot would best represent the data, this is because this isn't a large data set, it is relatively small, and because of that, the answer would be dot plot. dot plots are used for small amounts of data, and histograms are used for large amounts of data.

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A rectangular lawn has a diagonal path running across it. The lawn is 10m wide and 15m long. Work out the length of the path

Kisachek [45]

Answer:

d = 18.02 m

Step-by-step explanation:

Given that,

A rectangular lawn has a diagonal path running across it. The lawn is 10m wide and 15m long.

We need to find the length of the path.

The diagonal of a rectangle can be calculated as follows :

$d=\sqrt{10^2+15^2} \\\\d=18.02\ m$

So, the length of the path is 18.02 m.

5 0

3 years ago

Julia opened a new flower shop, and her daily sales are modeled by f(x) = 2(1.25)x. Determine the rate of growth.

hammer [34]

Answer:

D. 25%

Step-by-step explanation:

Each day, Julia's sales are 1.25 times the previous day's sales. That is, 25% more than the day before. Julia's sales are increasing 25% per day.

8 0

3 years ago

Read 2 more answers

Can someone PLZZZZ HELP!!!!

swat32

Answer:

The solution is:

Part A. $\sqrt{5}^{\frac{7k}{3}})$ which is sqrt(5)^7k/3[/tex]

Part B. k = 18/7

Step-by-step explanation:

Part A.

To solve this part, we're going two use THREE important properties of exponents:

1. $(x^{n})^{m} = x^{nm}$

2. $\frac{x^{n}}{x^{m}} = x^{n-m}$

3. $\sqrt[n]{x^{m}} = x^{\frac{m}{n} }$

Let's work the numerator using the properties 1, 2 and 3:

$(\sqrt{5}^{3} )^{\frac{k}{9} } } = (\sqrt{5}^{3\frac{k}{9}}) = (\sqrt{5}^{\frac{k}{3}})$

Let's work the denominator using the properties 1, 2 and 3:

$(\sqrt{5}^{6} )^{-\frac{k}{3} } } = (\sqrt{5}^{6\frac{k}{3}}) = (\sqrt{5}^(2k))$

Now dividing the numerator by the denominator:

$\sqrt{5}^{\frac{k}{3}-(-2k)})=\sqrt{5}^{\frac{7k}{3}})$

Part B

if $5^{\frac{3}{2} } 5^{\frac{3}{2}} = \sqrt{5}^{\frac{7k}{3}})$

Then:

$5^{3} = 5^{\frac{7k}{6}})$

So $\frac{7k}{6}} = 3$

Solving for k, we have:

k = 18/7

7 0

3 years ago

Augustus ruled the roman empire from 27 BC to AD 14.For how many years did he rule?<br><br><br>

Lyrx [107]

Answer:

41

Step-by-step explanation:

8 0

3 years ago

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Can you Order 4/5 2/3 and2/5

Galina-37 [17]

Answer:

in order of greatest to least

1) 4/5

2) 2/3

3) 2/5

:)

Step-by-step explanation:

7 0

4 years ago

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