Answer:
291666666667/100000000000
#2. (-10, 0) (-10, -8) (0, -8)
#3. (-10, 0) (-10, 8) (-7, 8)
#4. (-10, 0) (-7, 0) (-7, 8)
#8. (0, 8) (0, 0) (8, 0) (10, 4)
#9. (-7, 0) (-7, 8) (0, 8) (0, 0)
#10. (-10, 0) (0, 0) (0, -8)
Not sure about the others. Hope this helps, though.
Answer:
B. 20.8
Step-by-step explanation:
Just got it right on edge 2021
Answer:
The answer is "Through which we can infer that perhaps the ABC triangles is obstinate shaped".
Step-by-step explanation:
Paul draws that ABC as well as the Median triangle from and A and B nodes. If the median passes after a certain point, and his marks the point X. Paul now says point X (i.e., a triangle's center) is outside the ABC triangle.
They may also conclude that perhaps the ABC triangle does have an obtuse angle because the centroid is in the ring in case of even a severe triangle, that centroid is already on the right triangle in case of the triangle and cases of an obtuse-angled rectangle, the angular velocity is an outside ring.