Question

Compute your average velocity in the following two cases: (a) You walk 64.6 m at a speed of 1.20 m/s and then run 64.6 m at a speed of 3.53 m/s along a straight track. (b) You walk for 1.00 min at a speed of 1.20 m/s and then run for 1.78 min at 3.53 m/s along a straight track.

Answer 1

Answer:

Step-by-step explanation:

Given

(a)distance$(s_1)=64.6 m$

speed=1.2 m/s

$s_2$=64.6 at 3.53 m/s

total time $=\frac{64.6}{1.2}+\frac{64.6}{3.53}$

=53.83+18.3=72.13 s

Average velocity$=\frac{Displacement}{time}$

$V_{avg}=\frac{129.2}{72.13}=1.79 m/s$

(b)total distance$=60\times 1.2+106.8\times 3.53=72+377.004=449 m$

Average velocity$=\frac{Displacement}{time}$

$v_{avg}=\frac{449}{166.8}=2.69 m/s$