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2 years ago

11

Henry can write 5 1/4 pages of his novel in 3 hours how many page can he write in 8 hours

1 answer:

ICE Princess25 [194]2 years ago

8 0

If you would like to know how many pages can Henry write in 8 hours, you can calculate this using the following steps:

5 1/4 = 21/4 pages ... 3 hours
x pages = ? ... 8 hours

21/4 * 8 = 3 * x
21 * 2 = 3 * x
3 * x = 42
x = 42 / 3
x = 14 pages

Henry can write 14 pages of his novel in 8 hours.

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bn%5E5%7D%7Bn-6%7D%20%2A%20%5Cfrac%7Bn%5E2-6%7D%7Bn%5E8%7D" id="TexFormula1" title="\

ddd [48]

Step-by-step explanation:

Dod you mean

$= \frac{ {n}^{5} }{ {n}^{ - 2} } \times \frac{ {n}^{2 - 6} }{ {n}^{8} }$

$= {n}^{5 - ( - 2)} \times {n}^{2 - 6 - 8}$

$= {n}^{7} \times {n}^{ - 12}$

$= {n}^{7 + ( - 12)}$

$= {n}^{ - 5} = \frac{1}{ {n}^{5} }$

5 0

2 years ago

mixer [17]

Hope this help!!!

Have a nice day!!!

7 0

2 years ago

What is the seventh term of a geometric sequence that has a common ratio of –3 and the first term is –4?

rjkz [21]

An= A1 r ^(n-1)
An= -4 (-3)^(n-1)
An= -4 (-3)^(7-1)
An= -4 (729)
An= -2916

I think this is right :)

4 0

3 years ago

Please I really need help

san4es73 [151]

Answer:

its probably 2.0 or 0.2

Step-by-step explanation: x√=x−2

I really hope this helps i'm not that smart with this....

4 0

3 years ago

A square pyramid. The square base has side lengths of 6 inches. The 4 triangular sides have a base of 6 inches and height of 9 i

Marrrta [24]

Answer:

The area of the pyramid’s base is 36 in².

The pyramid has 4 lateral faces.

The surface area of each lateral face is 27 in².

Step-by-step explanation:

"<u>Lateral</u>" means side, so the lateral faces are <u>triangles</u>.

The <u>base</u> is the bottom, which is a <u>square</u>.

To calculate the <u>area of the base</u>, use the formula for area of a square.

$A_{base} = s^{2}$

$A_{base} = (6 in)^{2}$

$A_{base} = 36 in^{2}$

To calculate the <u>area of a lateral face</u>, find the area of a triangle.

$A_{lateral} = \frac{bh}{2}$

$A_{lateral} = \frac{(6 in)(9 in)}{2}$

$A_{lateral} = \frac{54 in^{2}}{2}$

$A_{lateral} = 27 in^{2}$

In a pyramid, the number of lateral faces is the same as the number of sides in the base. <u>The square base as 4 sides, so there are 4 lateral faces</u>.

3 0

3 years ago