25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
4 * 45 = 180
265 - 180 = 85
85/5 = 17
They sold 17 rolls of patterned wrapping paper.
2+3.25g=y
G would be the independent variable, which means the total cost would depend on it since it depends on the number of games you bowl. Y could be any variable, such as T or C.
2+3.25g=y
Answer:
i believe its 27
Step-by-step explanation:25 times two= 50 27 times two= 54 +one more is 55. so it is 27
