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Elina [12.6K]
3 years ago
8

What is the median of this set of data?NA66,51, 77, 68, 60, 75, 54, 80​

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
8 0
The median is of this set of data is 67
nadya68 [22]3 years ago
3 0

Answer:

The mean/average is 66.375

Step-by-step explanation:

<em><u>To find the median, add all of the numbers together.  Then, divide the total amount of numbers from that.</u></em>

<em><u /></em>

<u>Step 1:  Add all of the numbers together</u>

66 + 51 + 77 + 68 + 60 + 75 + 54 + 80

<em>531</em>

<em />

<u>Step 2:  Find out the total amount of numbers</u>

66, 51, 77, 68, 60, 75, 54, 80​

 1    2    3    4    5    6    7    8

<em>There are 8 numbers</em>

<em />

<u>Step 3:  Find the mean/average</u>

Total sum of numbers / Total amount of numbers

531 / 8

<em>66.375</em>

<em />

Answer:  The mean/average is 66.375

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Semmy [17]

Answer:

Solve by adding or subtracting like terms. (Ex. 2k + 4k = 6k; 9 + 7 = 16)

- 6k + 7k = 1k = k

(7 - 6 = 1)

12r - 8 - 12 = 12r - 20

(8 + 12 = 20 but sign is negative) 12r will stay the same because there are no terms with a letter r.

n - 10 + 9n - 3 = 9n + n - 10 - 3 = 10n - 10 - 3 = 10n - 13

(n = 1 so 9 + 1 = 10; 10 + 3 = 13 but negative sign)

- 4x - 10x = 14x

(10 + 4 = 14)

- r - 10r = 11r

(r = 1 so 10 + 1 = 11)

6 0
3 years ago
2(3x + 2) = 2x - 1+x.
andrew-mc [135]

Answer:

x = -5/3

Step-by-step explanation:

Hope this helps!

Best of luck!♥

5 0
2 years ago
Read 2 more answers
What is 25% of success as a fraction and a decimal
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People tend to evaluate the quality of their lives relative to others around them (Frieswijk et al., 2004). In one study, resear
Alborosie

Answer:

Step-by-step explanation:

Hello!

Research.

n=9 frail elderly were interview and compared to a fictitious person who was worse off then the interviewee, a life-satisfaction score was determined for each person.

18, 23, 24, 22, 19, 27, 23, 26, 25

Assuming that the population average score is μ= 20, the researchers think that the elderly in the sample are more or less satisfied than others in the general population.

a. You have the information of one sample, assuming this sample has a normal distribution and each elderly interviewed is independent, then the t-test of choice is a one-sample t-test.

b. and c. If you say that the elderly are "more or less" satisfied than the others, this means that they are either as satisfied as to the general population or not satisfied as to the general population. Symbolically:

H₀: μ = 20

H₁: μ ≠ 20

This is a two-tailed test, meaning, you will have two critical regions.

d.  

α: 0.05

Left critical value: t_{n-1;/\alpha 2} = t_{8; 0.025}= -2.306

Right critical value: t_{n-1;1-\alpha /2} = t_{8;0.975} = 2.306

e.

t_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}

X[bar]= 23

S= 3

t_{H_0}= \frac{23-20}{\frac{3}{\sqrt{9} } }= 3

f.

Considering that the calculated t-value is greater than the right critical value, the decision is to reject the null hypothesis, so using a significance level of 5% you can conclude that the average life-satisfaction score of the elderly is different than 20.

I hope it helps!

7 0
3 years ago
A local electronics store raised its prices on headphones by 20%. The headphones that Stan wants to buy now cost $36. How much d
atroni [7]
You would do 36$ -20% =28.8
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