Simple you get the area of the inner rectangle, then the area of the 2 semi circles then add them.
First, you need to notice that the diameter of each circle is same as the side of the rectangle (46m), also not that the 2 semi circles will make a complete one circle with radius (46/2)
so now we are left with the area of the rectangle+the area of a circle with radius of 32m
The total area= (46*92)+(3.14*(32^2))= 7447.36m^2
and to keep you significant figures the answer is rounded to 3 digits, so the final answer will be 745m^2.
Hope this helps, thanks.
Answer:
50 total
Step-by-step explanation:
when it's asking for a total you add the numbers together, and whatever number you get is your answer :)
sorry if it's wronggg :( !!
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
Remark
There is no short way to do this problem and no obvious way to get the answer other that to solve each part.
Solve
A
Multiply by 2
x + 1.6 = 2(x + 0.1) Remove the brackets
x + 1.6 = 2x + 0.1*2
x + 1.6 = 2x + 0.2 Subtract x from both sides
1.6 = x + 0.2 Subtract 0.2 from both sides
1.6 - 0.2 = x
1.4 = x
Circle A
B
Subtract 2x from both sides.
3x - 2x = 1.4
Circle B
C
Remove the brackets.
4x + 6 = 2x - 6 Add 6 to both sides
4x + 12 = 2x Subtract 4x from both sides.
12 = -2x Divide by - 2
12/-2 = x
x = - 6 Don't circle C
D
I'm going to be very scant in my solution of this. You can fill in the steps.
3x = 4.2
x = 4.2/3
x = 1.4
Circle D
Solutions
First Lets solve for this equation
Therefore this given equation is a <span>dependent system.
</span>
<span>Solve for </span>
There are too many solutions to these equations.