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3 years ago

Let p= x^2-7.

Mathematics

1 answer:

Advocard [28]3 years ago

8 0

Since p = x² - 7, you can substitute/plug in p for x² - 7

So:

(x² - 7)² - 4x² + 28 = 5

(p)² - 4x² + 28 = 5 You can factor out -4 from (-4x² + 28)

p² - 4(x² - 7) = 5 Plug in p

p² - 4p = 5 Subtract 5

p² - 4p - 5 = 0 Your answer is C

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3 years ago

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Answer:

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3 years ago

PLEASE HELP

notsponge [240]

Answer:

(a)

x cubed is

=x^3=x3

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the quotient of 4 times x and 3 is

=\frac{4x}{3}=34x

so,

the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3 is

=5x^3-\frac{4x}{3}=5x3−34x ..........Answer

(b)

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=5x^3=5x3

5 times cube of x divided by 4 times x is

=\frac{5x^3}{4x}=4x5x3 ..........Answer

(c)

difference of 5 times x cube and 4 is

=5x^3 -4=5x3−4

so,

the quotient of the difference of 5 times x cube and 4 and x is

=\frac{5x^3-4}{x}=x5x3−4 ...........Answer

(d)

difference of 5 times x and 4 is

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so,

the cube of the difference of 5 times x and 4 is is

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3 years ago

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4 years ago

Read 2 more answers