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o-na [289]
3 years ago
13

What is the mode of the data set shown below?

Mathematics
2 answers:
Novay_Z [31]3 years ago
8 0

Answer:

2, 5 and 6

Step-by-step explanation:

this is because mode is the most appeared number in a data and 2,5 and 6 all appeared twice

aivan3 [116]3 years ago
4 0
Answer: 2,5, and 6

Explanation: The mode is the number/numbers that occur frequently. In this data set you can see that 2,5, and 6 were used twice. Which makes these the modes.
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What is the answer to the qustion 0.3h+1.2=0.1h-2.6
andreev551 [17]

Answer:

-19

Step-by-step explanation:

0.3h+1.2=0.1h-2.6

.2h+1.2=-2.6

.2h=-3.8

h=-19

7 0
3 years ago
This the questions that have me stuck​
IRINA_888 [86]
First a and then b.
4 0
3 years ago
Can someone pls help me with this.
Elodia [21]

Answer:

[A] It will take 24 minutes for Joe and Charmaine to meet again at the starting line.

[B] Joe will complete 2 laps

[C]  Charmaine will complete 3 laps.

Step-by-step explanation:

Factor two numbers 12 and 8:

12 = 2×2×3

8 = 2×2×2

Find LCM of 12 and 8:

Lcm of 12 and 8 - 2×2×3×2 = 24

Therefore,

[A] How much time does it take for them to meet again at the starting line?

It will take 24 minutes for Joe and Charmaine to meet again at the starting line.

[B] How many laps does Joe complete

Joe will complete 2 laps

[C] How many laps does Charmaine complete?

Charmaine will complete 3 laps.

<u>~lenvy~</u>

6 0
2 years ago
a car travels at an average speed of 64 miles per hour. How long does it take to travel in 3 hours and 30 minute
enot [183]

Answer:

4 hours and 30 minutes 288/64 = 4,5

Step-by-step explanation:

4 0
2 years ago
Here are summary statistics for randomly selected weights of newborn​ girls: nequals202​, x overbarequals28.3 ​hg, sequals6.1 hg
Lorico [155]

Answer:

The confidence interval is 27.5 hg less than mu less than 29.1 hg

(A) Yes, because the confidence interval limits are not similar.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = 28.3 hg

sd = 6.1 hg

n = 202

degree of freedom = n-1 = 202-1 = 201

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value corresponding to 201 degrees of freedom and 5% significance level is 1.97196

E = t×sd/√n = 1.97196×6.1/√202 = 0.8 hg

Lower limit = mean - E = 28.3 0.8 = 27.5 hg

Upper limit = mean + E = 28.3 + 0.8 = 29.1 hg

95% confidence interval is (27.5, 29.1)

When mean is 28.3, sd = 6.1 and n = 202, the confidence limits are 27.5 and 29.1 which is different from 27.8 and 29.6 which are the confidence limits when mean is 28.7, sd = 1.8 and n = 17

7 0
3 years ago
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