By substitution,



and so on, so that
[tex]g(n)=6.1^{n-1}g(1)=2.7\cdot6.1^{n-1}
we know that
if the lines a and b are parallel lines cut by transversal f
then
--------> by alternate exterior angles
solve for x

therefore
<u>the answer is</u>
the value of x is 
The answer may or may not be B
Answer:
x^2+(y+16)^2=15
Step-by-step explanation:
(x-0)^2+{y-(-16)}^e=(√15)^2
→x^2+(y+16)^2=15
A = πr² + πrl
306.00 = 3.14(6)² + 3.14(6)(l)
306.00 = 3.14(36) + 3.14(6l)
306.00 = 113.04 + 18.84l
- 113.04 - 113.04
192.96 = 18.84l
18.84 18.84
10.24 ≈ l