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UNO [17]
3 years ago
10

How do you solve:

Mathematics
1 answer:
Molodets [167]3 years ago
8 0

Answer:

D? or B.

Step-by-step explanation:

sa iba ka nalang tanong

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Evaluate: −5−(x+y)2, where x=3 and y=6
insens350 [35]

Answer: -23

Step-by-step explanation:

-5-2x-2y

-5-2(3)-2(6)

-5-6-12 = -23

3 0
2 years ago
Need help on this question
bulgar [2K]
Solving using quadratic formula: x=4, -7/3

Factor by grouping: (3x+7)(x-4)
7 0
3 years ago
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Arada [10]

Answer:

Step-by-step explanation:

x = 16 and y = 625. Find (2\sqrt{x+y} )^{2}

(2\sqrt{16+625} )^{2} \\= (2\sqrt{641} )^{2} = 4*641 = 2564

8 0
3 years ago
How many total terms are there in the following sequence. 7,10,13,...,391,394
nlexa [21]

Answer: n = 130

Step-by-step explanation:

The sequence is an Arithmetic progression ( AP )

The last term of the sequence is (L) is 394 with the formula

L  = a + ( n- 1 )d . From the sequence, a = 7, d ( common difference ) = 3 and L ( last term ) = 394, and n = ?

Put those values in the formula above and solve for n.

  a + ( n - 1 )d =  L

  7 + ( n - 1 ) x 3  = 394

         7 + 3n - 3   = 394

             4 + 3n     = 394

                    3n     = 394 - 4

                     3n     = 390

                        n     = 130      

4 0
3 years ago
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How may different arrangements are there of the letters in ALASKA? 7 of 10 (5 complete) HW Score: 26.15% E Que The number of pos
Lubov Fominskaja [6]
<h2>Answer:</h2>

The number of possible arrangements is : 120

<h2>Step-by-step explanation:</h2>

We know that in order to find the different arrangements which are possible we need to use the method of permutation.

The arrangement of a given word is calculated as the ratio of the factorial of number of letters to the product of factorial of numbers the number of times each letter is repeating.

The word is given to be:

                    ALASKA

There are a total of 6 letters in the given word

Out of which a letter "A" is  repeating  3 times.

Hence, the number of arrangements possible are:

        =\dfrac{6!}{3!}\\\\\\=\dfrac{6\times 5\times 4\times 3!}{3!}\\\\\\=6\times 5\times 4\\\\\\=120

4 0
4 years ago
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