It takes 2 seconds to reach a maximum height of 69 feet, and the range is [5, 69].
The equation is of the form
h(t) = -16t² + v₀t + h₀, where -16 is the gravitational constant, v₀ is the initial velocity, and h₀ is the initial height. Using the values from our problem, we have:
h(t) = -16t² + 64t + 5
To find the maximum height, we find the vertex. The first step in this is to find the axis of symmetry, which is given by -b/2a:
-64/2(-16) = -64/-32 = 2
This is our value for t, so it takes 2 seconds to reach the maximum. Substituting this into our function, we have
h(2) = -16(2²) + 64(2) + 5 = -64 + 128 + 5 = 64 + 5 = 69
This is the maximum height.
The range of heights goes from 5 to 69, inclusive, or [5, 69].
Answer:
A) T is located on (-5, 2); radius = 9 units
Step-by-step explanation:
eqn of circle= (x-a)^2 + (y-b)^2 = r^2
where (a,b) is centre of circle.
(x+5)^2 = (x - (-5) )^2
(y-2)^2 = (y - (2) )^2
(-5,2)
r^2 =81
r = sqrt of 81
r = 9
1 fathom = 6 feet
2 1/2 fathoms = x feet
2 1/2 fathoms • 6 feet = x feet
x = 15
2 1/2 fathoms = 15 feet
For AD to be parallel 2x+4º should be equal to 79º
2(37)+4 = 78º
78º<79º
Since they aren't equal the lines are not parallel to each other.
