Answer:
it is 4 feet deep
Step-by-step explanation:
Answer: answer is B
Step-by-step explanation:
A= 300e(0.04)5
300e0.2
A=$365
Take the derititve
f'(x)=3x^2+6x-24
set to zero
0=3(x^2+2x-8)
0=3(x-2)(x+4)
at x=2 and -4
those are where the min and max are
ok so
sign chart
to the lft of -4, the sign is positive
betweeen -4 and 2, the sign is negative
tothe right of 2 the sign is positive
max=sign changef from (+) to (-)
min=sign change from (-) to (+)
so max at x=-4 and min at x=2
find x=2, the value is -28
answer is C
2. 4th degree so quartic (qua, like quad or quadrilatal)
2(4x-3) ≥ - 3(3x) + 5x
2* 4x - 2*3 ≥ - 9x + 5x
8 x - 6 ≥ -4x
8 x + 4 x ≥ 6
12 x ≥ 6
x = 6/12 divide 6/6 = 1 and 12 / 6 = 2
x = 1/2
hope this helps!
Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.