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3 years ago

What is the solution to the following equation? x+(-21)=8

Mathematics

2 answers:

Yuki888 [10]3 years ago

8 0

Answer:

x=29

Step-by-step explanation:

rodikova [14]3 years ago

3 0

Answer:

x is 29.

Step-by-step explanation:

x-21=8 (same equation to solve)

+21 +21 (add 21 to both sides)

-------------

x= 29

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We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal

ohaa [14]

Answer: AAA similarity.

Step-by-step explanation: CB is the transversal for the parallel lines AB and DE, and so by transverse property, we have ∠CED ≅ ∠CBA. Similarly, CA acts as a tranversal for the same pair of parallel lines AB and DE and using the same property, we can have ∠CDE ≅ ∠CAB. Now, in triangles CED and ABC, we have

∠CED ≅ ∠CBA,

∠CDE ≅ ∠CAB

and

∠DCE ≅ ∠ACB [same angle]

Hence, by AAA (angle-angle-angle) similarity,

△CED ~ △ABC.

Thus, the correct option is AAA similarity.

8 0

3 years ago

Read 2 more answers

How many different right triangles are there with a hypotenuse of lenght 5 cm

Sveta_85 [38]

Answer:

Draw a horizontal line across a page of paper, somewhere in the middle. Mark a point A on the line, toward the left margin.

Spread open a compass to make good sized circle, but so that if the point of the compass is on the point you drew, the pencil fits on the page, both below the top edge and to the left of the right edge of the page. Draw the arc, from roughly the 12 O’Clock position over and down to the intersection of the line segment, at the 3 O’Clock position.

Call the opening of your compass, the radius of the arc you just drew, “5 units”.

Pick any point on the arc between the 12 and 3 positions, B. Drop a line down from that point B, perpendicular to the original horizontal line. Label the point that it intersects the horizontal line, C.

ABC is a right triangle with hypotenuse 5. Do this again with a point a little closer to the 3 O’Clock position. It’s another right triangle with hypotenuse 5.

Indeed, as you get closer to the right, along the arc, the height of the triangle declines, but the width of the triangle increases. The hypotenuse remains 5 in all cases. We picked points on the circle. We could have picked points on the horizontal line first, and raised perpendicular lines until they intersected the circle. Each point forms a distinct right triangle.

There are as many possible right triangles as there are possible points in a line segment.

Step-by-step explanation:

6 0

3 years ago

Type the correct answer in the box. Use numerals instead of words.

Mandarinka [93]

Answer:

Step-by-step explanation:

We are here given a modulus expression and we need to find out the value when m = -5 and n = 3 .

Modulus :- It always gives positive value . For example ,

$\rm\implies |-a| = a$

$\rm\implies |a| = a$

The given modulus expression is :-

$\rm\implies |m^2+ n^2|$

As the number inside the modulus operator are already squared therefore they will always give positive value for real numbers . Here we can omit the modulus .

$\rm\implies m^2 + n^2$

Plug in the given values ,

$\rm\implies (-5)^2 + 3^2$

Solve 5² and 3² and add them ,

$\rm\implies 25 + 9$

On adding ,

$\rm\implies 34$

Therefore ,

$\rm\implies \boxed{\blue{\rm |m^2+n^2| = 34 }}$

Hence the required answer is 34 .

8 0

3 years ago

The outlier, 78, is removed from the data set shown.

bixtya [17]

Answer:

Well, in order o figure this out, you have to understand the definition or range.

Range is the difference between the lowest and highest values.

Since 78 use to be the highest number, the range was 55

Now when we remove the outlier, the new highest value is 45, decreasing the range to 22.

Hope this helps!

4 0

3 years ago

A large rectangular shaped swimming pool has a perimeter of 1020 meters and its length is 20 meters more than 6 times its width

ss7ja [257]

Perimeter = 1020 m
let width be = X
let length be = 20 + 6 (X)
perimeter of rectangle = 2 ( length + width )
1020 = 2 ( 20 + 6 X + X )
1020 = 2 ( 20 + 7 X )
1020 = 40 + 14 X
14 X = 1020 - 40
14 X = 980
X = 980 / 14 = 70

width = X = 70 meters
length = 20 + 6X = 20 + 6 ( 70 )
= 20 + 420
= 440 meters

HOPE IT HELPED !!

4 0

3 years ago