The expression is rewritten in standard form and they are not the same due to the negative.
<h3>What is simplification of an expression?</h3>
Usually, simplification involves proceeding with the pending operations in the expression.
Simplification usually involves making the expression simple and easy to use later.
Both (x−3)(x+3) and (3−x)(3+x) contain a sum and a difference and have only 3 and x in each factor.
Let see the equation formed by the factor;
(x−3)(x+3)
= x^2 + 3x - 3x - 9
= x^2 - 9
(3−x)(3+x)
= 9 + 3x - 3x - x^2
= 9 - x^2
The expression is rewritten in standard form and they are not the same due to the negative.
Learn more about an expression here:
brainly.com/question/1249625
#SPJ1
1. The complex number 6 + 7i has
- real part 6;
- imaginary part 7.
2. The complex number 10 + 2i has
- real part 10;
- imaginary part 2.
3. When we add two complex numbers, we add real parts and imaginary parts separately:
(6+7i)+(10+2i)=(6+10)+(7+2)i=16+9i.
Answer: 16+9i
Answer:
AB + BC = AC
BC = AC - AB
5x + 6 = 37 - (2 x + 3) = 37 -2 x - 3 = 34 - 2 x
7 x = 34 - 6 = 28
x = 4
BC = 5 x + 6 = 5 * 4 + 6 = 26
Check:
AB = 2 x + 3 = 2 * 4 + 3 = 11
AB + BC = 26 + 11 = 37
Cos( A + B ) = cosAcosB - sinAsinB ;
cos( A + B ) / ( cosAsinB ) = ( cosAcosB - sinAsinB ) / ( cosAsinB ) = ( cosAcosB ) / ( cosAsinB ) - ( sinAsinB ) / ( cosAsinB ) = cosB / sinB - sinA / cosA = cotB - tanA ;
Answer: A, B, C, D
Step-by-step explanation:
A. This is true because all rhombi are parallelograms, and diagonals of a parallelogram bisect each other.
B. This is true because the diagonals of a rhombus are perpendicular.
C. This is true because diagonals of a rhombus bisect the angles from which they are drawn,
D. This is true because all sides of a rhombus are congfruent.
E. This is not always true - all rhombi are parallelograms, and adjacent angles of a parallelogram are supplementary, but not always congruent.
F. This is not always true - diagonals of a rhombus are not always congruent.
