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Nata [24]
3 years ago
12

Among the cast aluminum parts manufactured on a certain day, 90% were flawless, 8% had only a minor flaw, and 2% had major flaws

. Suppose we select a random part from the production line. What is the probability that the part has at least one flaw
Mathematics
1 answer:
Andreyy893 years ago
3 0

Answer:

10% probability that the part has at least one flaw

Step-by-step explanation:

We have these following probabilities:

90% probability of the part being flawless.

8% probability of the part having a minor flaw

2% probability of the part having major flaws.

What is the probability that the part has at least one flaw

Minor or major flaws. So 8% + 2% = 10%

10% probability that the part has at least one flaw

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3 years ago
Which statement could be used in step 2 when proving x =
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Step-by-step explanation:

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8 0
3 years ago
What is the equation of the line that passes through the point (5, -6) and has a<br> slope of – 3/5
Inessa [10]

Answer:

The answer is

<h2>y =  -  \frac{6}{5} x - 3 \\</h2>

Step-by-step explanation:

To find an equation of a line when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1) \\

where

m is the slope

( x1 , y1) is the point

From the question the point is (5, -6) and slope - 3/5

The equation of the line is

y + 6 =  -  \frac{3}{5} (x - 5) \\ y + 6 =  -  \frac{3}{5} x + 3 \\ y =  -  \frac{6}{5} x + 3 - 6

We have the final answer as

y =  -  \frac{6}{5} x - 3 \\

Hope this helps you

3 0
3 years ago
Read 2 more answers
A cylinder and cone have the same height and radius. The height of each is 5 cm, and the radius is 2 cm. Calculate the volume of
never [62]

Answer:

The volume of a cylinder is 62.8 cm and the volume of a cone is 20.9 cm³ .

Step-by-step explanation:

Formula

Volume\ of\ a\ cylinder = \pi r^{2} h

Volume\ of\ a\ cone = \pi r^{2} \frac{h}{3}

Where r is the radius and h is the height .

As given

A cylinder and cone have the same height and radius. The height of each is 5 cm, and the radius is 2 cm.

\pi = 3.14

Thus

Volume\ of\ a\ cylinder =3.14\times 5\times 2\times 2

                                             = 62.8 cm³

Thus the volume of a cylinder is 62.8 cm³ .

Volume\ of\ a\ cone = 3.14\times 2\times 2\times frac{5}{3}

Volume\ of\ a\ cone =\frac{5\times 3.14\times 2\times 2}{3}

Volume\ of\ a\ cone =\frac{62.8}{3}

                                        = 20.9 (Approx) cm³

Thus the volume of a cone is 20.9 cm³ .

Therefore the volume of a cylinder is 62.8 cm and the volume of a cone is 20.9 cm³ .

8 0
3 years ago
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3 years ago
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