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3 years ago

F(x)=1/2x+2.i need help

Mathematics

1 answer:

m_a_m_a [10]3 years ago

8 0

Answer: If you want to find the x and y intercepts, your answer would be...

x-intercept - (-4,0)

y-intercept - (0,2)

Step-by-step explanation:

To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.

I hope this helps you out! ☺

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If f(x) = 8 – 10x and g(x) = 5x + 4, what is the value of (fg)(–2)?

Vedmedyk [2.9K]

F(x) = 8 - 10x

g(x) = 5x + 4

Finding (fg)(-2).

First let us find fg(x), this is the same as f(g(x))

f(g(x))

f(5x + 4)

Recall, f(x) = 8 - 10x, therefore f(5x + 4) would be such that anywhere we see x in the f(x), we replace it with 5x + 4

f(x) = 8 - 10x

f(5x +4) = 8 - 10(5x + 4)

   = 8 - 50x - 40

   = -50x + 8 - 40

   = -50x - 32

f(g(x)) = fg(x) = -50x - 32

fg(-2) = -50*(-2) - 32 = 100 - 32 = 68

Therefore fg(-2) = 68

I hope this helped.

5 0

3 years ago

Find two numbers whose sum is 9 and whose difference is -1

faltersainse [42]

Answer:

4 and 5

Step-by-step explanation:

Make a system of equations:

x+y=9

x-y=-1

x=9-y

9-y-y=-1

9-2y=-1

-2y=-10

y=5

Since y=5, x must be 4 since 4+5=9 and 4-5=-1

Hope this helped!

4 0

3 years ago

Read 2 more answers

Apply the Distributive property:<br><img src="https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%203%28x-4%29%3D2%28-2x%2B1%29%20%7D" i

jenyasd209 [6]

Answer:

x = 2

Step-by-step explanation:

The left side would be (3x - 12)
The right side would be (-4x+2)

In an equation, 3x - 12 = -4x+2

Combine all the letters on the left and plain numbers on the right,

3x + 4x = 12 + 2

Note: When you transfer to the other side of the equal sign, the number will change its sign.

Simplify the 3x + 4x = 12 + 2,

7x = 14

$x=\frac{14}{7}$

x = 2

5 0

2 years ago

Read 2 more answers

3 out of every 5 picks are orange. If 12 picks are orange, how many picks are there in all?

alexandr1967 [171]

Answer:

the are 15 orange ones

4 0

3 years ago

How would I find the integral of <img src="https://tex.z-dn.net/?f=%5Cint%5Cfrac%7Btdt%7D%7Bt%5E4%2B2%7D" id="TexFormula1" title

kotegsom [21]

Let $t=\sqrt y$ , so that $t^2=y$ , $t^4=y^2$ , and $\mathrm dt=\dfrac{\mathrm dy}{2\sqrt y}$ . Then

$\displaystyle\int\frac t{t^4+2}\,\mathrm dt=\int\frac{\sqrt y}{2\sqrt y(y^2+2)}\,\mathrm dy=\frac12\int\frac{\mathrm dy}{y^2+2}$

Now let $y=\sqrt2\tan z$ , so that $\mathrm dy=\sqrt2\sec^2z\,\mathrm dz$ . Then

$\displaystyle\frac12\int\frac{\mathrm dy}{y^2+2}=\frac12\int\frac{\sqrt2\sec^2z}{(\sqrt2\tan z)+2}\,\mathrm dz=\frac{\sqrt2}4\int\frac{\sec^2z}{\tan^2z+1}\,\mathrm dz=\frac1{2\sqrt2}\int\mathrm dz=\dfrac1{2\sqrt2}z+C$

Transform back to $y$ to get

$\dfrac1{2\sqrt2}\arctan\left(\dfrac y{\sqrt2}\right)+C$

and again to get back a result in terms of $t$ .

$\dfrac1{2\sqrt2}\arctan\left(\dfrac{t^2}{\sqrt2}\right)+C$

3 0

3 years ago