Answer:
Step-by-step explanation:
The point of this question is to find out the point where two lines intersect. First we need to get the equation of those lines
Slope of line 1:
(Yb -Ya)/(Xb - Xa) =
(-10 - (-14))/(-1 - (-3)) =
4/2 =
2
Use that slope to find the Y-intercept of line 1
y = 2x + b
-14 = 2(-3) +b
-14 = -6 + b
-8 = b
Therefore Line 1 is:
y = 2x - 8
Slope of line 2
(11 - 13)/(-1 - (-3)) =
-2/2 =
-1
Y-intercept of line 2
y = -x + b
13 = -(-3) +b
13 = 3 + b
10 = b
Therefore line 2 is
y = -x + 10
Now we have 2 equations to solve for the coordinates x and y
y = 2x - 8
y = -x + 10
Substitute y out in one of the equations
2x - 8 = -x + 10
3x = 18
x = 6
Plug x into one of the equations
y = 2(6) - 8
y = 12 - 8
y = 4
Therefore the solution is:
x=6, y=4
Answer:
Expand: x² + 11x + 11x + 121
Simplify: x² + 22x + 121
Step-by-step explanation:
To expand this, you can use the FOIL technique:
First terms
Outer terms
Inner terms
Last terms
(x+11)(x+11)
F - x*x = x²
O - x*11 = 11x
I - 11*x = 11x
L - 11*11 = 121
Put these numbers together (expanded) to get:
x² + 11x + 11x + 121
Put the common terms together (simplify) to get:
x² + 22x + 121
Note:
Not sure if you need this info, but (x + 11)(x + 11) is the same as (x + 11)².
The numbers need to be in the order I put them in because you are supposed to place them in order greatest to least degree.
Hope it helps!
2nd point distance-1st point distant
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