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slava [35]
2 years ago
6

Find the value of X

Mathematics
1 answer:
kap26 [50]2 years ago
7 0

Answer:

x = 27

Step-by-step explanation:

We can say that sum of all interior angles adds up to: 180°, therefore;

(3x - 17) + (2x - 5) + (x + 40) = 180°

=> now add like terms together:

=> 3x + 2x + x = 6x

=> -17 + (-5) + 40 = 18

Therefore;

6x + 18 = 180°

6x = 180 - 18

6x = 162

x = 162/6

<u>x = 27</u>

Hope this helps!

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The temperature was -7 degrees in the morning. By noon, it was 12 degrees outside. What was the change in temperature?
11111nata11111 [884]

Answer:

19 degrees

Step-by-step explanation:

12-(-7)= 19

(12+7=19)

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Simplify the following rational expression
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Answer:

= 5 (-2y+3) / -y+3

Step-by-step explanation:

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3 years ago
910/14=? please solve.
Nookie1986 [14]

910 \div 14 = 65
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Complete the problem​
nika2105 [10]

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2 years ago
At a large Midwestern university, a simple random sample of 100 entering freshmen in 1993 found that 20 of the sampled freshmen
guajiro [1.7K]

Answer:

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

p1 -> 1993

20 out of 100, so:

p_1 = \frac{20}{100} = 0.2

s_1 = \sqrt{\frac{0.2*0.8}{100}} = 0.04

p2 -> 1997

10 out of 100, so:

p_2 = \frac{10}{100} = 0.1

s_2 = \sqrt{\frac{0.1*0.9}{100}} = 0.03

Distribution of p1 – p2:

p = p_1 - p_2 = 0.2 - 0.1 = 0.1

s = \sqrt{s_1^2+s_2^2} = \sqrt{0.04^2 + 0.03^2} = 0.05

Confidence interval:

p \pm zs

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.  

The lower bound of the interval is:

p - zs = 0.1 - 1.645*0.05 = 0.01775&#10;

The upper bound of the interval is:

p + zs = 0.1 + 1.645*0.05 = 0.18225&#10;

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

6 0
3 years ago
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