1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
disa [49]
3 years ago
12

Find the value of in each of the following x/5+1=5

Mathematics
1 answer:
Alisiya [41]3 years ago
5 0
X is 20 because 20/5 is 4 n 4+1=5
You might be interested in
Help me please!!!!!
nadya68 [22]
Man tbh wth is this at this point just trow that mug out the window
5 0
3 years ago
Conditional Distribution, Marginal Distribution, Joint Distribution. <br> What’s the difference?
lutik1710 [3]

Explanation:

Marginal distribution: This distribution gives the probability for each possible value of the Random variable ignoring other random variables. Basically, the values of other variables is not considered in the marginal distribution, they can be any value possible. For example, if you have two variables X and Y, the probability of X being equal to a value, lets say, 4, contemplates every possible scenario where X is equal to 4, independently of the value Y has taken. If you want the probability of a dice being a multiple of 3, you are interested that the dice is either 3 or 6, but you dont care if the dice is even or odd.

Conditional distribution: This distribution contrasts from the previous one in the sense that we are restricting the universe of events to specific condition for other variable, making a modification of our marginal results. If we know that throwing a dice will give us a result higher than 2, then to in order to calculate the probability of the dice being a multiple of 3 using that condition, we have two favourable cases (3 and 6) from 4 total possible results (3,4,5 and 6) discarding the impossible values (1 and 2) from this universe since they dont match the condition given (note that the restrictions given can also reduce the total of favourable cases).

The joint distribution calculates the probabilities for two different events (related to two different random variables) occuring simultaneously. If we want to calculate the joint probability of a dice being multiple of 3 and greater than 2 at the same time, our possible cases in this case are 3 and 6 from 6 possible results. We are not discarding 1 or 2 as possible results because we are not assuming, that the dice is greater than 2, that is another condition that we should met in the combination of events.

3 0
3 years ago
Your family is going on a road trip to Disney World! On Day 1, you traveled x miles. On Day 2, you drove 58 miles more than 3 ti
Eva8 [605]

Answer:i need help with this also

Step-by-step explanation:

8 0
3 years ago
If x = y + z and x + y =6 and x = 10, then z = _____?
7nadin3 [17]
X+y=6
x=10

10+y=6
y=-4

10=-4+z
-4+z=10
z=10+4
z=14

So the correct answer is 14
4 0
4 years ago
Read 2 more answers
How must m2 be changed to keep the lines parallel?
Anna [14]

Answer:

bring the lines side by side ( example || )

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • Shirley graphed the line shown on the coordinate plane.
    12·1 answer
  • PLEASE HELP!! 25 POINTS
    12·1 answer
  • Find the x- and y- intercepts of 4x +5y = 20. Indicate which answer is the x-intercept and which answer is the y-intercept.
    7·1 answer
  • Select the correct answer.<br> Solve this inequality for x: -46 − 8x &gt; 22.
    15·1 answer
  • 0.00014s in scientific notation? ...?
    7·2 answers
  • Plz help______________
    10·2 answers
  • Help Find the fourth angle. PLEASE and thanks!!
    5·2 answers
  • Written assignment: answer these questions. 30 points for correct answer. hagd (may or may not do brainliest)
    9·1 answer
  • Find the mean: 17.4 mm, 20.3 mm, 84.1 mm, 31.2 mm, 53.7 mm, 11.7 mm
    11·1 answer
  • How can we know that number or the answer without calculator ?​
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!