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3 years ago

2x-9x+17=-4 I have a answer but I’m not sure if I’m correct so I just want to double check.

Mathematics

2 answers:

andrey2020 [161]3 years ago

8 0

Answer:

x=3

Step-by-step explanation:

subtract 2x and 9x ( 2x-9x= -7x)
subtract 17 and -4 ( -4 -17= -21)
divide -21 and -7 ( -21 / -7= -3)
x=3

vova2212 [387]3 years ago

3 0

Answer: x = 3

Step-by-step explanation: Simplify both sides

2x - 9x + 17 = -4

2x + - 9x + 17 = -4

Combine like terms

(2x + -9x) (17) = -4

-7x + 17 = -4

Subtract 17 from both sides

-7x + 17 - 17 = -4 - 17

-7x = -21

Divide both sides by -7

-7x/-7 = -21/-7

x = 3

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3 years ago

Least the containers from least to greatest capacity; 1.73, 2.061, 1.59, 2.1

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Answer:

1.59 < 1.73 < 2.061 < 2.1

Step-by-step explanation:

Hello,

We know that 2 is higher than 1. So to pick the first ones we know it won't be the two numbers starting with a 2. We are left with two numbers : 1.73 and 1.59. <u>In this case we can multiply these two numbers by 100. We are allowed to do this only if we do it to all the numbers we are trying to figure out.</u> In this case, it is 1.73 and 1.59 (we are excluding the 2s). So we end up with : 173 and 159. This might help you. We obviously know that 173 is a larger number than 159.

So, we then proceed to the numbers starting with a 2. <u>In this case we can multiply both by 1,000 considering the fact that the number 2.061 has 3 digits after the dot.</u> This will make it easier for us. When we multiply both by 1,000 we end up with 2,061 and 2,100. We obviously know that 2,061 is smaller than 2,100.

I hope this helped

Kind regards,

Clém

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3 years ago

Find the exact values of sin2 θ for cos θ = 3/18 on the interval 0° ≤ θ ≤ 90°

mote1985 [20]

Answer:

$sin(2\theta)=\frac{\sqrt{35} }{18}$

Step-by-step explanation:

Recall the formula for the sine of the double angle:

$sin(2\theta)=2*sin(\theta)*cos(\theta)$

we know that $cos(\theta)=\frac{3}{18}$ , and that $\theta$ is in the interval between 0 and 90 degrees, where both the functions sine and cosine are non-negative numbers. Based on such, we can find using the Pythagorean trigonometric property that relates sine and cosine of the same angle, what $sin(\theta)$ is:

$cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }$

With this information, we can now complete the value of the sine of the double angle requested:

$sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}$

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