Answer:
630
Step-by-step explanation:
you need to do a 2 step equation, first finding the amount of students that get accepted, and then use the info you just got solving how many people actually enroll.
formula:
part part %
---------- = -----------
total total %
The formula we use for continuous compounding is

where P is the initial amount invested, r is the rate as a decimal, and t is time in years. Our P = 1300, our r = .042, and our t = 5.75 (9 months is 3/4 of a year, and 3/4 in a decimal is .75). Putting all that into our formula we have

. We have to multiply those 2 powers together and then raise euler's number to it, then multiply by 1300. Doing all of that, we get the amount at the end to be $1,655.10
Answer: The answer is 3n + 2
Step-by-step explanation: You will have to combine like terms:
=−n + −4 + 4n + 6
=(−n + 4n) + (−4 + 6)
=3n + 2
The sqrt of (34 m^4) is sqrt(34) times sqrt(m^4).
The sqrt of m^4 is easy ... that's just m^2 .
The other part is more messy. There's not much you can do with it.
sqrt(34) = sqrt(17) times sqrt(2).
That doesn't help make it any simpler.
You might as well just leave it as sqrt(34).
Then the final, simplified form of the original expression is
m^2 sqrt(34)